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# If u < v < w and x < y < z, is v < y?

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Math Expert
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If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 02:57
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Difficulty:

35% (medium)

Question Stats:

78% (00:52) correct 22% (00:59) wrong based on 49 sessions

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Competition Mode Question

If $$u < v < w$$ and $$x < y < z$$, is $$v < y$$?

(1) $$u < x$$

(2) $$w < x$$

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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 03:15
1
Statement is not sufficient because from the question stem v>u. We are unable to tell if x<u or x>u.

Statement 2 is sufficient. w<x is sufficient because w<x means u<x since v<w. In addition y>x hence we can conclude that v<y.

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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 03:20
1
If u<v<w and x<y<z, is v<y?

From Statement (1)
u<x
=> u<x<y<z
we do not anything about v here
Hence Insufficient.

Eliminate option (A) and (D)

From Statement (2)
w<x
=> w<x<y<z
Since u<v<w

=>u<v<w<x<y<z

=> v<y
Hence Sufficient

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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 03:40
2
Answer is option B.This is how I solved.

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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 04:07
If u < v < w and x < y < z, is v < y?

(1) u < x

(2) w < x

For v < y any of the following conditions is necessary
a. w < x
b. w < y

Statement 1) u < x

Possibilities are as follows:
I. u < x < v < w < y < z i.e. v < y
II. u < x < y < v < w < z i.e. v > y

Since it results in both Yes and No answer statement is INSUFFICIENT.

Statement 2) w < x

Possibilities are as follows:
I. u < v < w < x < y < z i.e. v < y

i.e. only one conditions.

Also, this statement matches point ‘a’, hence it is SUFFICIENT.

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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 05:11
If u<v<w and x<y<z, is v<y?

(1) u<x

(2) w<x

#1
u<x ; not sufficient as y may or may not be y>v not possible always
#2
w<x ; sufficient to say that y>v
IMO B
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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 05:45
Given:
1. u<v<w
2. x<y<z

(1) u<x
u<x<y<z;
u<v<w;
There is no relation known between x<y<z and v<w
NOT SUFFICIENT

(2) w<x
u<v<w<x<y<z
v<y
SUFFICIENT

IMO B
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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 06:09
Given u < v < w and x < y < z

Consider (1) u<x : x value can be <y or >y .....clearly insufficient
Consider (2) w<x : implies clearly that v<x so v<y .....sufficient

OA: (B)
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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 06:13

Because If u<v<w and x<y<z and w<x then V has to be < y.

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Re: If u < v < w and x < y < z, is v < y?  [#permalink]

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28 Aug 2019, 12:15
Statement 1:
If u<v<w and x<y<z, is v<y?

(1) u<x possible scenarios
a) u<x<v<y<..
b) u<x<y<v<..
Not sufficient

(2) w<x
greatest on 1st equation is less than smallest of second
only one scenario is possible
u<v<w <x<y<z
Hence sufficient
Re: If u < v < w and x < y < z, is v < y?   [#permalink] 28 Aug 2019, 12:15
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