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Bunuel
If \(v\) is \(\frac{1}{2}\) of \(3w\), \(2w\) is \(\frac{1}{3}\) of \(4x\), \(3x\) is \(\frac{1}{4}\) of \(5y\), and \(4y\) is \(\frac{1}{5}\) of \(6z\), then \(5v\) is what fraction of \(7z\) ?

A. 1/61

B. 5/56

C. 5/6

D. 1/6

E. 5/8


Are You Up For the Challenge: 700 Level Questions

v = 3w/2
2w = 4x/3
3x = 5y/4
4y = 6z/5
5v = k 7z
k = ?
5v = 15w/2 = 5x = 25y/12 = 25z/40 = 5z/8 = (5/56)7z

IMO B

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Bunuel
If \(v\) is \(\frac{1}{2}\) of \(3w\), \(2w\) is \(\frac{1}{3}\) of \(4x\), \(3x\) is \(\frac{1}{4}\) of \(5y\), and \(4y\) is \(\frac{1}{5}\) of \(6z\), then \(5v\) is what fraction of \(7z\) ?

A. 1/61

B. 5/56

C. 5/6

D. 1/6

E. 5/8


Are You Up For the Challenge: 700 Level Questions

The LCD of all the given fractions is 120, so a smart choice for z is 120; thus:

4y = 6 * z/5

4y = 6 * 120 / 5

y = 36

Then:

3x = 9 * 5

x = 15

Then:

2w = 5 * 4

w = 10

Then:

v = 3 * 5 = 15

Thus,

5v/7z = (5 * 15)/(7 * 120) = 15/(7 * 24) = 5/56

Answer: B
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v/w* w/x*y/x*y/z = v/z

v/w = 3/2
w/x = 4/6 = 2/3
x/y = 5/12
y/z = 6/20 = 3/10

3/2 * 2/3 * 5/12 * 3/10 = 5/12 *3/10 = 15/120 = 1/8

v/z = 1/8

5v/7z = 1/8*5/7 = 5/56
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why did we do multiplication in the end of all
nick1816
\(\frac{v}{w}=\frac{3}{2}=\frac{15}{10}\)

\(\frac{w}{x}=\frac{2}{3}=\frac{10}{15}\)

\(\frac{x}{y}=\frac{5}{12}=\frac{15}{36}\)

\(\frac{y}{z}=\frac{3}{10}=\frac{36}{120}\)

\(\frac{v}{w} * \frac{w}{x} * \frac{x}{y} * \frac{y}{z}\) = \(\frac{15}{10} * \frac{10}{15} * \frac{15}{36} * \frac{36}{120 }\)

\(\frac{v}{z} = \frac{15}{120} = \frac{1}{8 }\)

\(\frac{5v}{7z}= \frac{5}{7} * \frac{v}{z}= \frac{5}{56}\)



Bunuel
If \(v\) is \(\frac{1}{2}\) of \(3w\), \(2w\) is \(\frac{1}{3}\) of \(4x\), \(3x\) is \(\frac{1}{4}\) of \(5y\), and \(4y\) is \(\frac{1}{5}\) of \(6z\), then \(5v\) is what fraction of \(7z\) ?

A. 1/61

B. 5/56

C. 5/6

D. 1/6

E. 5/8


Are You Up For the Challenge: 700 Level Questions
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shubhim20
why did we do multiplication in the end of all
nick1816
\(\frac{v}{w}=\frac{3}{2}=\frac{15}{10}\)

\(\frac{w}{x}=\frac{2}{3}=\frac{10}{15}\)

\(\frac{x}{y}=\frac{5}{12}=\frac{15}{36}\)

\(\frac{y}{z}=\frac{3}{10}=\frac{36}{120}\)

\(\frac{v}{w} * \frac{w}{x} * \frac{x}{y} * \frac{y}{z}\) = \(\frac{15}{10} * \frac{10}{15} * \frac{15}{36} * \frac{36}{120 }\)

\(\frac{v}{z} = \frac{15}{120} = \frac{1}{8 }\)

\(\frac{5v}{7z}= \frac{5}{7} * \frac{v}{z}= \frac{5}{56}\)

Bunuel
If \(v\) is \(\frac{1}{2}\) of \(3w\), \(2w\) is \(\frac{1}{3}\) of \(4x\), \(3x\) is \(\frac{1}{4}\) of \(5y\), and \(4y\) is \(\frac{1}{5}\) of \(6z\), then \(5v\) is what fraction of \(7z\) ?

A. 1/61
B. 5/56
C. 5/6
D. 1/6
E. 5/8

We multiply in the end to combine all the chain ratios into a single ratio from v to z.

Each step links two variables: v to w, w to x, x to y, y to z

By multiplying all those ratios, all the middle terms (w, x, y) cancel out, leaving just v to z.
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