GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 18 Nov 2019, 22:27

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

If vmt≠0, is v^2*m^3*t^(-4)>0?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Intern
Intern
avatar
Joined: 09 Jul 2010
Posts: 9
If vmt≠0, is v^2*m^3*t^(-4)>0?  [#permalink]

Show Tags

New post 21 Jul 2010, 18:06
4
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

72% (01:11) correct 28% (01:25) wrong based on 368 sessions

HideShow timer Statistics

If vmt≠0, is v^2*m^3*t^(-4)>0?

(1) m > v^2
(2) m > t^(-4)
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 59125
Re: Another DS problem.  [#permalink]

Show Tags

New post 21 Jul 2010, 18:16
1
1
If \(v*m*t\) not \(= 0\), is \(v^2*m^3*t^{-4} > 0\)?

\(v*m*t\neq{0}\) means that none of the unknowns equals to zero.

Is \(v^2*m^3*t^{-4}>0\)? --> is \(\frac{v^2*m^3}{t^4}> 0\)? As \(v^2\) and \(t^4\) are positive (remember none of the unknowns equals to zero) this inequality will hold true if and only \(m^3>0\), or, which is the same, when \(m>0\).

(1) \(m>v^2\) --> \(m\) is more than some positive number (\(v^2\)), hence \(m\) is positive. Sufficient.

(2) \(m>t^{-4}\) --> \(m>\frac{1}{t^4}\) --> Again \(m\) is more than some positive number (\(\frac{1}{t^4}\) ), hence \(m\) is positive. Sufficient.

Answer: D.

Hope it's clear.
_________________
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 59125
Re: If vmt≠0, is v^2*m^3*t^(-4)>0?  [#permalink]

Show Tags

New post 17 Jun 2013, 05:02
Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE


_________________
Manager
Manager
avatar
Joined: 20 Jun 2012
Posts: 73
Location: United States
Concentration: Finance, Operations
GMAT 1: 710 Q51 V25
GMAT ToolKit User
Re: If vmt≠0, is v^2*m^3*t^(-4)>0?  [#permalink]

Show Tags

New post 17 Jun 2013, 20:36
1
sstudy wrote:
If vmt≠0, is v^2*m^3*t^(-4)>0?

(1) m > v^2
(2) m > t^(-4)


This is a very easy question. I would say 500-600 level.

Question asks whether [(v^2)(m^3)]/(t^4) is greater than 0 or not. here, whether the value of expression is +ve or not depends only on sign of "m" as we know neither of the three is "0"

1. in first option "m" is given greater than square of something. Hence m is +ve.

2. same as first. m could be less then 1 but still positive.
_________________
Forget Kudos ... be an altruist
Manager
Manager
User avatar
S
Joined: 25 Mar 2013
Posts: 225
Location: United States
Concentration: Entrepreneurship, Marketing
GPA: 3.5
GMAT ToolKit User Reviews Badge
If vmt ≠ 0, is v^2m^3t^4 > 0?  [#permalink]

Show Tags

New post Updated on: 29 Jul 2014, 22:23
If vmt ≠ 0, is v^2m^3t^4 > 0?
(1) m > \(v^2\)
(2) m >\(t^4\)

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
_________________
I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you

Originally posted by kanusha on 29 Jul 2014, 22:19.
Last edited by Gnpth on 29 Jul 2014, 22:23, edited 1 time in total.
Manager
Manager
User avatar
Joined: 04 Sep 2012
Posts: 91
Location: Philippines
Concentration: Marketing, Entrepreneurship
Schools: Ross (Michigan) - Class of 2017
GMAT 1: 620 Q48 V27
GMAT 2: 660 Q47 V34
GMAT 3: 700 Q47 V38
GPA: 3.25
WE: Sales (Manufacturing)
GMAT ToolKit User
Re: If vmt ≠ 0, is v^2m^3t^4 > 0?  [#permalink]

Show Tags

New post 29 Jul 2014, 23:11
1
kanusha wrote:
If vmt ≠ 0, is v^2m^3t^4 > 0?
(1) m > \(v^2\)
(2) m >\(t^4\)

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


Based on the question stem, \(m^3\) is the only element that needs to be evaluated to check if the entire equation is positive.

Statement 1: The only time that \(m>v^2\) is when m is positive. Sufficient
Statement 2: The only time that \(m>t^4\) is when m is positive. Sufficient

Note: Anything raised to an even number is always positive. (This means that regardless of sign, v & t will end up positive anyway)

Answer is D
Intern
Intern
avatar
Joined: 25 Jul 2014
Posts: 2
Re: If vmt ≠ 0, is v^2m^3t^4 > 0?  [#permalink]

Show Tags

New post 29 Jul 2014, 23:22
kanusha wrote:
Can any one solve this in simpliest Way,helpful for me

Thank you.



vmt ≠ 0, so we know that v, m, and t must all be either a positive or negative number, but cannot be 0.

(1) The value of m is greater than v^2. Whether we set v at a positive or negative number, it's square will be positive.
m has to be positive because it must be greater than v. With two positive numbers multiplied together, the only way that v^2m^3t^4 can be less than zero is if t^4 was negative. Since it is multiplied by an even exponent, t^4 will be a positive number regardless if t is negative or positive. Therefore, if (1) is valid, the solution can only be positive, for a "yes" response. Sufficient.

(2) If the value of m is greater than t^4, then both numbers must be positive, and again since v^2 is an even exponent, the square will be a positive number. Again, the only valid solution is a greater than zero, resulting in only a "yes" response. This is similar to (1). Sufficient.

Both statements are sufficient alone.
Answer: D
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 59125
Re: If vmt≠0, is v^2*m^3*t^(-4)>0?  [#permalink]

Show Tags

New post 29 Jul 2014, 23:43
kanusha wrote:
If vmt ≠ 0, is v^2m^3t^4 > 0?
(1) m > \(v^2\)
(2) m >\(t^4\)

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


Merging topics. Please refer to the solution above.

P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to rules 1 and 3. Thank you.


_________________
Non-Human User
User avatar
Joined: 09 Sep 2013
Posts: 13604
Re: If vmt≠0, is v^2*m^3*t^(-4)>0?  [#permalink]

Show Tags

New post 14 Nov 2018, 00:10
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Bot
Re: If vmt≠0, is v^2*m^3*t^(-4)>0?   [#permalink] 14 Nov 2018, 00:10
Display posts from previous: Sort by

If vmt≠0, is v^2*m^3*t^(-4)>0?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne