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23 May 2020, 06:29
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If \(x ≠ 0\), is \(\frac{1}{x} < \frac{1}{x^2}\)?
(1) \(x > 0 \)
(2) \(0 < x < 1\)
DS21242
(1) \(x > 0 \)
(2) \(0 < x < 1\)
DS21242
23 May 2020, 06:34
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Bunuel
If \(x ≠ 0\), is \(\frac{1}{x} < \frac{1}{x^2}\)?
(1) \(x > 0 \)
(2) \(0 < x < 1\)
PS21242
(1) \(x > 0 \)
(2) \(0 < x < 1\)
PS21242
Question: Is 1/x < 1/x^2?
1/x will always be less than 1/x^2 whenever
I) x < 0
II) 0 < x < 1
I) x < 0
II) 0 < x < 1
Ststement 1: \(x > 0 \)
x may be 1/2 (YES)
x may be 2 (NO)
NOT SUFFICIENT
Statement 2: \(0 < x < 1\)
SUFFICIENT
Answer: Option B
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23 May 2020, 07:04
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If x≠0, is 1/x < 1/x^2?
Statement 1: x> 0
Clearly insufficient since:
if x = 2,3
then 1/x > 1/x^2,
but if x = 1/2,1/3
then 1/x < 1/x^2, since => 2< 2^2.
So the given statement could be true or false.
So Insufficient.
Statement 2: 0<x<1.
This gives us a range of numbers in which only fractional numbers are present.
Thus we can say for sure that Yes , 1/x < 1/x^2.
So Sufficient.
Answer B.
Statement 1: x> 0
Clearly insufficient since:
if x = 2,3
then 1/x > 1/x^2,
but if x = 1/2,1/3
then 1/x < 1/x^2, since => 2< 2^2.
So the given statement could be true or false.
So Insufficient.
Statement 2: 0<x<1.
This gives us a range of numbers in which only fractional numbers are present.
Thus we can say for sure that Yes , 1/x < 1/x^2.
So Sufficient.
Answer B.
