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# If x > 0, what is the value of x^5 ?

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Math Expert
Joined: 02 Sep 2009
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If x > 0, what is the value of x^5 ?  [#permalink]

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06 Oct 2016, 05:01
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If x > 0, what is the value of x^5 ?

(1) $$\sqrt{x}=32$$
(2) x^2 = 2^20

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Re: If x > 0, what is the value of x^5 ?  [#permalink]

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06 Oct 2016, 08:04
x is positive; x^5 = ?

St1: sqrt(x) = 2^5
x = 2^10
x^5 = (2^10)^5 = 2^50
Sufficient

St2: x^2 = 2^20
x = 2^10
x^5 = 2^50
Sufficient

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Re: If x > 0, what is the value of x^5 ?  [#permalink]

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06 Oct 2016, 08:20
Bunuel wrote:
If x > 0, what is the value of x^5 ?

(1) $$\sqrt{x}=32$$
(2) x^2 = 2^20

IMO D
Given x>0

From statement 1
Squaring x=2^10
x^5=2^50 Sufficient

From statement 2
x^2=2^20 implies x=2^10
x^5=2^50 Sufficient
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Joined: 02 Sep 2016
Posts: 41
Re: If x > 0, what is the value of x^5 ?  [#permalink]

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06 Oct 2016, 10:01
1
IMO D must be the answer.
1. √x=32 -->x=32^2 (since √x=|x| and hence always positive) . Therefore x^5=32^10. Sufficient
2. x^2 = 2^20 --> x=+2^10 or -2^10. Since x>0--> x^5 will be positive. Sufficient.
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Re: If x > 0, what is the value of x^5 ?  [#permalink]

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06 Oct 2016, 23:06
D.
Din approach for answer
Answer 1 and 2 both gives values of x .. so we can find x^5.
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Re: If x > 0, what is the value of x^5 ?  [#permalink]

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07 Oct 2016, 08:13
In my opinion the correct answer is D.
(1) would be sufficient even if we didn't know that x is positive.
(2) is sufficient because we have x positive.
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If x > 0, what is the value of x^5 ?  [#permalink]

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08 Oct 2016, 13:10
2
Bunuel wrote:
If x > 0, what is the value of x^5 ?

(1) $$\sqrt{x}=32$$
(2) x^2 = 2^20

We are given that x is greater than zero and need to determine the value of x^5.

Statement One Alone:

√x = 32

Using the equation in statement one, we can determine a value of x.

√x = 32

(√x)^2 = 32^2

x = 32^2 = (2^5)^2 = 2^10

Since x = 2^10, x^5 = (2^10)^5 = 2^50

Statement one alone is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone:

x^2 = 2^20

Using the equation in statement two, we can determine a value of x.

√(x^2) = +/-√(2^20)

x = +/-2^10

Since x is positive, x = 2^10.

Since x = 2^10, x^5 = (2^10)^5 = 2^50.

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If x > 0, what is the value of x^5 ?  [#permalink]

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25 Jul 2018, 07:38
Bunuel wrote:
If x > 0, what is the value of x^5 ?

(1) $$\sqrt{x}=32$$
(2) x^2 = 2^20

Hey Bunuel,

Just wanted to understand that in Statement 2 when we are taking the square root, why can't the right side of the equation take 2 values of +/- underoot 2^20?
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Posts: 57191
Re: If x > 0, what is the value of x^5 ?  [#permalink]

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25 Jul 2018, 08:22
Bunuel wrote:
If x > 0, what is the value of x^5 ?

(1) $$\sqrt{x}=32$$
(2) x^2 = 2^20

Hey Bunuel,

Just wanted to understand that in Statement 2 when we are taking the square root, why can't the right side of the equation take 2 values of +/- underoot 2^20?

Check the highlighted part above.
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Re: If x > 0, what is the value of x^5 ?  [#permalink]

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06 Aug 2019, 22:52
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Re: If x > 0, what is the value of x^5 ?   [#permalink] 06 Aug 2019, 22:52
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