Bunuel wrote:

If x > 0, what is the value of x^5 ?

(1) \(\sqrt{x}=32\)

(2) x^2 = 2^20

We are given that x is greater than zero and need to determine the value of x^5.

Statement One Alone:√x = 32

Using the equation in statement one, we can determine a value of x.

√x = 32

(√x)^2 = 32^2

x = 32^2 = (2^5)^2 = 2^10

Since x = 2^10, x^5 = (2^10)^5 = 2^50

Statement one alone is sufficient to answer the question. We can eliminate answer choices B, C, and E.

Statement Two Alone:x^2 = 2^20

Using the equation in statement two, we can determine a value of x.

√(x^2) = +/-√(2^20)

x = +/-2^10

Since x is positive, x = 2^10.

Since x = 2^10, x^5 = (2^10)^5 = 2^50.

Answer: D

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