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# If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/

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Math Expert
Joined: 02 Sep 2009
Posts: 52433
If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/  [#permalink]

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03 Sep 2017, 05:03
00:00

Difficulty:

45% (medium)

Question Stats:

68% (02:26) correct 32% (02:27) wrong based on 158 sessions

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If $$\sqrt{x} =20$$ and $$\sqrt{y} =16$$, then $$\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=$$

A. $$9\sqrt{41}$$

B. 2

C. $$\frac{9\sqrt{41}}{41}$$

D. 1

E. 9/41

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Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/  [#permalink]

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03 Sep 2017, 06:59
1
Bunuel wrote:
If $$\sqrt{x} =20$$ and $$y = \sqrt{16}$$, then $$\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=$$

A. $$9\sqrt{41}$$

B. 2

C. $$\frac{9\sqrt{41}}{41}$$

D. 1

E. 9/41

Hi Bunuel,

Is there a mistake with the question? Or am i doing something wrong?
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Joined: 02 Sep 2009
Posts: 52433
Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/  [#permalink]

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03 Sep 2017, 07:04
pushpitkc wrote:
Bunuel wrote:
If $$\sqrt{x} =20$$ and $$y = \sqrt{16}$$, then $$\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=$$

A. $$9\sqrt{41}$$

B. 2

C. $$\frac{9\sqrt{41}}{41}$$

D. 1

E. 9/41

Hi Bunuel,

Is there a mistake with the question? Or am i doing something wrong?

_______________
Edited. Thank you.
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Math Expert
Joined: 02 Aug 2009
Posts: 7213
Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/  [#permalink]

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03 Sep 2017, 07:13
Bunuel wrote:
If $$\sqrt{x} =20$$ and $$\sqrt{y} =16$$, then $$\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=$$

A. $$9\sqrt{41}$$

B. 2

C. $$\frac{9\sqrt{41}}{41}$$

D. 1

E. 9/41

Hi

$$\sqrt{x} =20.....x=400$$ and $$\sqrt{y} =16,.....y=256$$,
$$\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=\frac{20+16}{√(400+256)}=\frac{36}{√656}=\frac{36}{4√41}=\frac{9√41}{41}$$

C
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2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

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Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/  [#permalink]

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19 Sep 2018, 00:42
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/ &nbs [#permalink] 19 Sep 2018, 00:42
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