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If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/

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If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/ [#permalink]

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If \(\sqrt{x} =20\) and \(\sqrt{y} =16\), then \(\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=\)


A. \(9\sqrt{41}\)

B. 2

C. \(\frac{9\sqrt{41}}{41}\)

D. 1

E. 9/41
[Reveal] Spoiler: OA

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Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/ [#permalink]

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New post 03 Sep 2017, 07:59
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Bunuel wrote:
If \(\sqrt{x} =20\) and \(y = \sqrt{16}\), then \(\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=\)


A. \(9\sqrt{41}\)

B. 2

C. \(\frac{9\sqrt{41}}{41}\)

D. 1

E. 9/41



Hi Bunuel,

Is there a mistake with the question? Or am i doing something wrong?
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Kudos [?]: 738 [1], given: 19

Expert Post
Math Expert
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Joined: 02 Sep 2009
Posts: 42536

Kudos [?]: 135189 [0], given: 12671

Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/ [#permalink]

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New post 03 Sep 2017, 08:04
pushpitkc wrote:
Bunuel wrote:
If \(\sqrt{x} =20\) and \(y = \sqrt{16}\), then \(\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=\)


A. \(9\sqrt{41}\)

B. 2

C. \(\frac{9\sqrt{41}}{41}\)

D. 1

E. 9/41


Hi Bunuel,

Is there a mistake with the question? Or am i doing something wrong?


_______________
Edited. Thank you.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135189 [0], given: 12671

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Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/ [#permalink]

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New post 03 Sep 2017, 08:13
Expert's post
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Bunuel wrote:
If \(\sqrt{x} =20\) and \(\sqrt{y} =16\), then \(\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=\)


A. \(9\sqrt{41}\)

B. 2

C. \(\frac{9\sqrt{41}}{41}\)

D. 1

E. 9/41



Hi

\(\sqrt{x} =20.....x=400\) and \(\sqrt{y} =16,.....y=256\),
\(\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x+y}}=\frac{20+16}{√(400+256)}=\frac{36}{√656}=\frac{36}{4√41}=\frac{9√41}{41}\)

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Re: If x^(1/2) = 20 and y^(1/2) = 16, then (x^(1/2) + y^(1/2))/   [#permalink] 03 Sep 2017, 08:13
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