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Bunuel
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but 100 prime number will be even becase 99 odd will give you Even number and even + even is even
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KESHU99W
If x = -1 and n is the sum of the first 100 prime numbers, what is the value of \(x^n + x^{n+1}+x^{n+2}\)?
A. -2
B. -1
C. 0
D. 1
E. 2

but 100 prime number will be even becase 99 odd will give you Even number and even + even is even

Yes, the sum of the first 100 prime numbers will be odd, so n will be odd. So, we'd have:

\(x^n + x^{n+1}+x^{n+2}=\)

\(=(-1)^{odd} + (-1)^{even}+(-1)^{odd}=\)

\(=(-1) + 1 + (-1)= -1\)

Answer: B,

Hope it helps.
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There are 25 prime numbers less than 100.

2+3+5+7+11+13+17+19+23+29+31+37+41+43+47+53+59+61+67+71+73+79+83+89+97 = 1060

Sum of all these numbers is 1060 and hence an even number.
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There are 25 prime numbers less than 100.

2+3+5+7+11+13+17+19+23+29+31+37+41+43+47+53+59+61+67+71+73+79+83+89+97 = 1060

Sum of all these numbers is 1060 and hence an even number.
n is the sum of the first 100 prime numbers, not the sum of the primes less than 100.
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