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# Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the

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Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink]

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19 Dec 2015, 07:42
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Math Revolution and GMAT Club Contest Starts!

QUESTION #13:

If x=-1 and n is the sum of the second 101 prime numbers, what is the value of $$x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}$$?

A. -2
B. -1
C. 0
D. 1
E. 2

Check conditions below:

[Reveal] Spoiler:

Math Revolution and GMAT Club Contest

The Contest Starts November 28th in Quant Forum

We are happy to announce a Math Revolution and GMAT Club Contest

For the following four (!) weekends we'll be publishing 4 FRESH math questions per weekend (2 on Saturday and 2 on Sunday).

To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific.
Then a week later, the forum moderator will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6-months access to GMAT Club Tests.

PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize:

PS + DS course with 502 videos that is worth $299! All announcements and winnings are final and no whining GMAT Club reserves the rights to modify the terms of this offer at any time. NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process. Thank you! [Reveal] Spoiler: OA _________________ Kudos [?]: 135988 [0], given: 12719  Math Revolution Discount Codes e-GMAT Discount Codes EMPOWERgmat Discount Codes Intern Joined: 30 Sep 2013 Posts: 22 Kudos [?]: 16 [1], given: 4 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 19 Dec 2015, 08:59 1 This post received KUDOS There are total 25 prime numbers from 1 to 100 There are total 26 prime numbers from 1 to 101 Now given , " second 101 prime numbers " , I think that prime number starts from 3 to 101 . Excluding 2 [first prime number] List of second 101 prime numbers are 3,5,7,11,13,17.....101 There are total 25 second 101 primer numbers. If we can calculate n as even or odd, that will results into the solution as X = -1 Sum of second 2 prime numbers is even Sum of second 3 prime numbers is odd Sum of second 4 prime numbers is even Sum of second 5 prime numbers is odd . . . . Sum of second 25 prime numbers is odd There n is odd. x^n + x^(n+1) + x^(n+2) + x^(n+3) is (-1)^odd + (-1)^(odd + 1) + (-1)^(odd + 2) + (-1)^(odd + 3) -1 + (-1)^(even) + (-1)^(odd) + (-1)^(even) -1 + 1 - 1 + 1 0 Answer is C Kudos [?]: 16 [1], given: 4 Director Joined: 21 May 2013 Posts: 560 Kudos [?]: 54 [1], given: 507 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 19 Dec 2015, 09:13 1 This post received KUDOS n=sum of second 101 prime numbers Now , all prime numbers except 2 are odd. Therefore, sum of odd no of prime nos=odd and sum of even no of prime nos=even Therefore, sum of second 101 primes nos(in which all are odd)=odd or n=odd Reqd equation= -1+1-1+1=0 Answer C Kudos [?]: 54 [1], given: 507 Intern Joined: 12 Jul 2015 Posts: 27 Kudos [?]: 32 [2], given: 456 Location: United States Concentration: Strategy, General Management WE: General Management (Pharmaceuticals and Biotech) Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 19 Dec 2015, 10:05 2 This post received KUDOS Given: x=-1 n = Sum of the second 101 prime nos In the second set of 101 prime nos, 1. There are no even nos 2. Sum of any two odd nos is a Even no Since n is the sum of 101 prime nos, n = odd Now, (-1)^n+(-1)^(n+1)+(-1)^(n+2)+(-1)^(n+3) As n = odd, n+1= Even n+2=Odd n+3=Even and (-1)^odd = (-1), and (-1)^Even = +1 On Solving, -1+1-1+1=0 Alternatively, irrespective of whether n= odd/even, ans =0 Case 1: n = odd, n+1 = Even ,n+2 = odd, n+3 = Even (-1+1-1+1 = 0) Case 2: n = Even, n+1 = odd, n+2 = Even, n+3 = Odd (-1+1-1+1 = 0) Ans =C = 0 Kudos [?]: 32 [2], given: 456 Manager Joined: 20 Jan 2015 Posts: 59 Kudos [?]: 57 [1], given: 13 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 19 Dec 2015, 23:40 1 This post received KUDOS First, the sum of second 101 prime numbers needs to be calculated. Now, second 101 prime numbers means that the 101 prime numbers after 2. We also know that the sum of the 101 prime numbers after 2 will be an odd number since all these prime numbers are odd. => n is odd. Now to find the value = (-1)^odd + (-1)^even + (-1)^odd + (-1)^even = -1 + 1 + (-1) + 1 = 0 Option C. _________________ Please take a moment to hit Kudos if you like my post Kudos [?]: 57 [1], given: 13 Intern Joined: 21 Jan 2013 Posts: 46 Kudos [?]: 10 [1], given: 68 Concentration: General Management, Leadership Schools: LBS GPA: 3.82 WE: Engineering (Computer Software) Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 20 Dec 2015, 03:42 1 This post received KUDOS If x=-1 and n is the sum of the second 101 prime numbers, what is the value of xn+x(n+1)+x(n+2)+x(n+3)? A. -2 B. -1 C. 0 D. 1 E. 2 ---- x = -1 ; n = sum of second 101 "prime" numbers; Given that all prime numbers above 2 are ODD , sum of 101 second prime numbers is a sum of ALL ODD INTEGERS, odd integer + odd integer = even integer Extending this observation, sum of EVEN NUMBER of odd INTEGERS is always EVEN, sum of ODD number of ODD INTEGERS is always ODD. Therefore, we need not really deduce the value of n, but we can infer that n is definitely an ODD integer. Plugging it back into the equation, we're looking at (-1)^(odd) + (-1)^(even) + (-1)^(odd) + (-1)^(even) = -1 + (+1) + (-1) + (+1) = 0 Correct answer : C _________________ -- Consider +1 Kudos if you find my post useful Kudos [?]: 10 [1], given: 68 Intern Joined: 01 Nov 2015 Posts: 37 Kudos [?]: 21 [1], given: 59 Location: India Concentration: Marketing, Entrepreneurship WE: Engineering (Computer Software) Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 20 Dec 2015, 18:22 1 This post received KUDOS Since n is the sum of 2nd 101 Prime Numbers, n Must be Odd Therefore, (-1)^odd + (-1)^even + (-1)^odd + (-1)^even =-1 +1 -1 +1 = 0 Answer is C Kudos [?]: 21 [1], given: 59 SC Moderator Joined: 13 Apr 2015 Posts: 1511 Kudos [?]: 1240 [1], given: 896 Location: India Concentration: Strategy, General Management WE: Information Technology (Consulting) Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 21 Dec 2015, 00:45 1 This post received KUDOS x = -1 n = Sum of second 101 prime numbers is odd. (odd + odd + .... 101 times = odd) Now, the question can be rephrased as --> (-1)^odd + (-1)^even + (-1)^odd + (-1)^(even) = -1 + 1 - 1 + 1 = 0 Answer: C Kudos [?]: 1240 [1], given: 896 Manager Joined: 09 Jul 2015 Posts: 58 Kudos [?]: 33 [1], given: 61 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 21 Dec 2015, 16:41 1 This post received KUDOS Answer is C. xn+x(n+1)+x(n+2)+x(n+3) can be written as x^n(1+x+x^2+x^3). Apply x=-1 in this equation. (-1)^n*(1-1+1-1) = 0. Hence answer is 0. _________________ Please kudos if you find this post helpful. I am trying to unlock the tests Kudos [?]: 33 [1], given: 61 Intern Joined: 21 Nov 2014 Posts: 31 Kudos [?]: 48 [1], given: 20 Location: Viet Nam GMAT 1: 760 Q50 V44 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 22 Dec 2015, 01:34 1 This post received KUDOS Since n is an integer, in $$n, (n+1), (n+2), (n+3)$$ there will be two odd numbers and two even numbers. $$-1^{2k} = 1$$ and $$-1^{(2k+1)} = -1$$ => $$x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)} = 0$$, as it's the sum of two (-1) and two (1) Answer C. _________________ GMAT Group for Vietnamese: https://www.facebook.com/groups/644070009087525/ Kudos [?]: 48 [1], given: 20 Retired Moderator Joined: 23 Sep 2015 Posts: 403 Kudos [?]: 96 [1], given: 72 Location: France GMAT 1: 690 Q47 V38 GMAT 2: 700 Q48 V38 WE: Real Estate (Mutual Funds and Brokerage) Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 23 Dec 2015, 05:56 1 This post received KUDOS We are looking for the sum of 4 consecutive powers of x. - Since n in the sum of prime numbers, n is an integer. (in this case, excluding prime number 2, n is odd) however we don't need to know that. - Since x is negative, the even powers will yield 1 and the odd powers -1. Therefore the answer will always be zero: 1-1+1-1=0 and -1+1-1+1 =0 answer C _________________ New Application Tracker : update your school profiles instantly! Kudos [?]: 96 [1], given: 72 Intern Joined: 17 Aug 2014 Posts: 10 Kudos [?]: 9 [1], given: 1 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 24 Dec 2015, 09:06 1 This post received KUDOS 1 This post was BOOKMARKED The answer is 0 What ever may be the value of n ( either odd or even), the expression x^n+x^n+1+x^n+2+x^n+3 will have two even power of x and two odd powers of x. Since x is -1, the expression reduces to +1+1-1-1=0 (order can vary ) Kudos [?]: 9 [1], given: 1 Intern Joined: 05 Jun 2013 Posts: 35 Kudos [?]: 28 [1], given: 0 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 25 Dec 2015, 04:33 1 This post received KUDOS x=-1 n = the sum of the second 101 prime numbers, value of xn+x(n+1)+x(n+2)+x(n+3) Except 2, all prime numbers are odd.So sum of all odd numbers 101 times is again odd . So n is odd number. (-1)^odd number + (-1)^even number + (-1)^odd number + (-1)^even number = 0 which is answer choice C. Kudos [?]: 28 [1], given: 0 Moderator Joined: 21 Jun 2014 Posts: 956 Kudos [?]: 490 [1], given: 113 Location: India Concentration: General Management, Technology GMAT 1: 540 Q45 V20 GPA: 2.49 WE: Information Technology (Computer Software) Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 25 Dec 2015, 12:53 1 This post received KUDOS Given: x = -1 x^n + x^(n+1) + x^(n+2) + x^(n+3) can be re-written as the following by taking x^n as common: = x^n ( 1 + x + x^2 + x^3) - put the value of x = (-1)^n * ( 1 + (-1) + (-1)^2 + (-1)^3) = (-1)^n * 0 = 0 Option C is the correct answer. _________________ --------------------------------------------------------------- Target - 720-740 http://gmatclub.com/forum/information-on-new-gmat-esr-report-beta-221111.html http://gmatclub.com/forum/list-of-one-year-full-time-mba-programs-222103.html Kudos [?]: 490 [1], given: 113 Math Expert Joined: 02 Sep 2009 Posts: 42652 Kudos [?]: 135988 [0], given: 12719 Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink] ### Show Tags 27 Dec 2015, 11:21 Expert's post 2 This post was BOOKMARKED Bunuel wrote: Math Revolution and GMAT Club Contest Starts! QUESTION #13: If x=-1 and n is the sum of the second 101 prime numbers, what is the value of $$x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}$$? A. -2 B. -1 C. 0 D. 1 E. 2 Check conditions below: [Reveal] Spoiler: Math Revolution and GMAT Club Contest The Contest Starts November 28th in Quant Forum We are happy to announce a Math Revolution and GMAT Club Contest For the following four (!) weekends we'll be publishing 4 FRESH math questions per weekend (2 on Saturday and 2 on Sunday). To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific. Then a week later, the forum moderator will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6-months access to GMAT Club Tests. PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize: PS + DS course with 502 videos that is worth$299!

All announcements and winnings are final and no whining GMAT Club reserves the rights to modify the terms of this offer at any time.

NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.

Thank you!

MATH REVOLUTION OFFICIAL SOLUTION:

The sum of the second 101 prime numbers is the sum of the all prime numbers from the second prime number to the next 101 prime numbers. Except 2, every prime number is an odd number. So, n=3+5+…………..+prime=odd.

Then, $$x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}=(-1)^{odd}+(-1)^{even}+(-1)^{odd}+(-1)^{even}=(-1)+1+(-1)+1=0$$, and the correct answer is C.
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Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink]

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07 Mar 2016, 03:00
[quote="Bunuel"][quote="Bunuel"]

Math Revolution and GMAT Club Contest Starts!

QUESTION #13:

If x=-1 and n is the sum of the second 101 prime numbers, what is the value of $$x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}$$?

A. -2
B. -1
C. 0
D. 1
E. 2

Answer is Zero Irrespective of the value of N
_________________

Give me a hell yeah ...!!!!!

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Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink]

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11 Jul 2016, 05:52
Probably a stupid question: What does "second" mean here? I got the question right but just by plugging in -1 due to gutfeeling

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Math Expert
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Posts: 42652

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Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink]

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11 Jul 2016, 06:12
expertesp wrote:
Probably a stupid question: What does "second" mean here? I got the question right but just by plugging in -1 due to gutfeeling

Agree the wording could be clearer.

The sum of the second 101 prime numbers is the sum of the all prime numbers from the second prime number to the next 101 prime numbers. Except 2, every prime number is an odd number. So, n=3+5+…………..+prime=odd.
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Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink]

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11 Jul 2016, 13:37
Thank you!

So add on to this what does "25 second 101 primer numbers" stand for?
Also one I figured out there is 25 prime numbers between 2 and 101 exclusive why do I plug in 1 for n? Which I did because of my gutfeeling but I rather have a mathematical explanation

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Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the [#permalink]

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26 Sep 2017, 01:09
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Re: Math Revolution and GMAT Club Contest! If x=-1 and n is the sum of the   [#permalink] 26 Sep 2017, 01:09
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