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Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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19 Dec 2015, 08:42
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Math Revolution and GMAT Club Contest Starts! QUESTION #13:If x=1 and n is the sum of the second 101 prime numbers, what is the value of \(x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}\)? A. 2 B. 1 C. 0 D. 1 E. 2 Check conditions below: Math Revolution and GMAT Club ContestThe Contest Starts November 28th in Quant Forum We are happy to announce a Math Revolution and GMAT Club Contest For the following four (!) weekends we'll be publishing 4 FRESH math questions per weekend (2 on Saturday and 2 on Sunday). To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific. Then a week later, the forum moderator will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6months access to GMAT Club Tests. PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize: PS + DS course with 502 videos that is worth $299! All announcements and winnings are final and no whining GMAT Club reserves the rights to modify the terms of this offer at any time. NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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19 Dec 2015, 09:59
There are total 25 prime numbers from 1 to 100 There are total 26 prime numbers from 1 to 101
Now given , " second 101 prime numbers " , I think that prime number starts from 3 to 101 . Excluding 2 [first prime number]
List of second 101 prime numbers are 3,5,7,11,13,17.....101 There are total 25 second 101 primer numbers.
If we can calculate n as even or odd, that will results into the solution as X = 1
Sum of second 2 prime numbers is even Sum of second 3 prime numbers is odd Sum of second 4 prime numbers is even Sum of second 5 prime numbers is odd . . . . Sum of second 25 prime numbers is odd
There n is odd.
x^n + x^(n+1) + x^(n+2) + x^(n+3) is
(1)^odd + (1)^(odd + 1) + (1)^(odd + 2) + (1)^(odd + 3)
1 + (1)^(even) + (1)^(odd) + (1)^(even)
1 + 1  1 + 1
0
Answer is C



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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19 Dec 2015, 10:13
n=sum of second 101 prime numbers Now , all prime numbers except 2 are odd. Therefore, sum of odd no of prime nos=odd and sum of even no of prime nos=even Therefore, sum of second 101 primes nos(in which all are odd)=odd or n=odd Reqd equation= 1+11+1=0 Answer C



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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19 Dec 2015, 11:05
Given: x=1 n = Sum of the second 101 prime nos
In the second set of 101 prime nos, 1. There are no even nos 2. Sum of any two odd nos is a Even no
Since n is the sum of 101 prime nos, n = odd
Now, (1)^n+(1)^(n+1)+(1)^(n+2)+(1)^(n+3)
As n = odd, n+1= Even n+2=Odd n+3=Even and (1)^odd = (1), and (1)^Even = +1
On Solving, 1+11+1=0
Alternatively, irrespective of whether n= odd/even, ans =0 Case 1: n = odd, n+1 = Even ,n+2 = odd, n+3 = Even (1+11+1 = 0) Case 2: n = Even, n+1 = odd, n+2 = Even, n+3 = Odd (1+11+1 = 0)
Ans =C = 0



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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20 Dec 2015, 00:40
First, the sum of second 101 prime numbers needs to be calculated. Now, second 101 prime numbers means that the 101 prime numbers after 2. We also know that the sum of the 101 prime numbers after 2 will be an odd number since all these prime numbers are odd. => n is odd. Now to find the value = (1)^odd + (1)^even + (1)^odd + (1)^even = 1 + 1 + (1) + 1 = 0 Option C.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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20 Dec 2015, 04:42
If x=1 and n is the sum of the second 101 prime numbers, what is the value of xn+x(n+1)+x(n+2)+x(n+3)? A. 2 B. 1 C. 0 D. 1 E. 2  x = 1 ; n = sum of second 101 "prime" numbers; Given that all prime numbers above 2 are ODD , sum of 101 second prime numbers is a sum of ALL ODD INTEGERS, odd integer + odd integer = even integer Extending this observation, sum of EVEN NUMBER of odd INTEGERS is always EVEN, sum of ODD number of ODD INTEGERS is always ODD. Therefore, we need not really deduce the value of n, but we can infer that n is definitely an ODD integer. Plugging it back into the equation, we're looking at (1)^(odd) + (1)^(even) + (1)^(odd) + (1)^(even) = 1 + (+1) + (1) + (+1) = 0 Correct answer : C
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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20 Dec 2015, 19:22
Since n is the sum of 2nd 101 Prime Numbers, n Must be Odd
Therefore, (1)^odd + (1)^even + (1)^odd + (1)^even =1 +1 1 +1 = 0
Answer is C



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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21 Dec 2015, 01:45
x = 1
n = Sum of second 101 prime numbers is odd. (odd + odd + .... 101 times = odd)
Now, the question can be rephrased as > (1)^odd + (1)^even + (1)^odd + (1)^(even) = 1 + 1  1 + 1 = 0
Answer: C



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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21 Dec 2015, 17:41
Answer is C. xn+x(n+1)+x(n+2)+x(n+3) can be written as x^n(1+x+x^2+x^3). Apply x=1 in this equation. (1)^n*(11+11) = 0. Hence answer is 0.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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22 Dec 2015, 02:34
Since n is an integer, in \(n, (n+1), (n+2), (n+3)\) there will be two odd numbers and two even numbers. \(1^{2k} = 1\) and \(1^{(2k+1)} = 1\) => \(x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)} = 0\), as it's the sum of two (1) and two (1) Answer C.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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23 Dec 2015, 06:56
We are looking for the sum of 4 consecutive powers of x.  Since n in the sum of prime numbers, n is an integer. (in this case, excluding prime number 2, n is odd) however we don't need to know that.  Since x is negative, the even powers will yield 1 and the odd powers 1. Therefore the answer will always be zero: 11+11=0 and 1+11+1 =0 answer C
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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24 Dec 2015, 10:06
The answer is 0 What ever may be the value of n ( either odd or even), the expression x^n+x^n+1+x^n+2+x^n+3 will have two even power of x and two odd powers of x. Since x is 1, the expression reduces to +1+111=0 (order can vary )



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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25 Dec 2015, 05:33
x=1 n = the sum of the second 101 prime numbers, value of xn+x(n+1)+x(n+2)+x(n+3) Except 2, all prime numbers are odd.So sum of all odd numbers 101 times is again odd . So n is odd number.
(1)^odd number + (1)^even number + (1)^odd number + (1)^even number = 0
which is answer choice C.



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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25 Dec 2015, 13:53
Given: x = 1x^n + x^(n+1) + x^(n+2) + x^(n+3) can be rewritten as the following by taking x^n as common: = x^n ( 1 + x + x^2 + x^3)  put the value of x = (1)^n * ( 1 + (1) + (1)^2 + (1)^3) = (1)^n * 0 = 0 Option C is the correct answer.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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27 Dec 2015, 12:21
Bunuel wrote: Math Revolution and GMAT Club Contest Starts! QUESTION #13:If x=1 and n is the sum of the second 101 prime numbers, what is the value of \(x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}\)? A. 2 B. 1 C. 0 D. 1 E. 2 Check conditions below: Math Revolution and GMAT Club ContestThe Contest Starts November 28th in Quant Forum We are happy to announce a Math Revolution and GMAT Club Contest For the following four (!) weekends we'll be publishing 4 FRESH math questions per weekend (2 on Saturday and 2 on Sunday). To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific. Then a week later, the forum moderator will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6months access to GMAT Club Tests. PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize: PS + DS course with 502 videos that is worth $299! All announcements and winnings are final and no whining GMAT Club reserves the rights to modify the terms of this offer at any time. NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.
Thank you! MATH REVOLUTION OFFICIAL SOLUTION:The sum of the second 101 prime numbers is the sum of the all prime numbers from the second prime number to the next 101 prime numbers. Except 2, every prime number is an odd number. So, n=3+5+…………..+prime=odd. Then, \(x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}=(1)^{odd}+(1)^{even}+(1)^{odd}+(1)^{even}=(1)+1+(1)+1=0\), and the correct answer is C.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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07 Mar 2016, 04:00
[quote="Bunuel"][quote="Bunuel"] Math Revolution and GMAT Club Contest Starts! QUESTION #13:If x=1 and n is the sum of the second 101 prime numbers, what is the value of \(x^n + x^{(n+1)} + x^{(n+2)} + x^{(n+3)}\)? A. 2 B. 1 C. 0 D. 1 E. 2 Answer is Zero Irrespective of the value of N
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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11 Jul 2016, 06:52
Probably a stupid question: What does "second" mean here? I got the question right but just by plugging in 1 due to gutfeeling



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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11 Jul 2016, 07:12
expertesp wrote: Probably a stupid question: What does "second" mean here? I got the question right but just by plugging in 1 due to gutfeeling Agree the wording could be clearer. The sum of the second 101 prime numbers is the sum of the all prime numbers from the second prime number to the next 101 prime numbers. Except 2, every prime number is an odd number. So, n=3+5+…………..+prime=odd.
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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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11 Jul 2016, 14:37
Thank you! So add on to this what does "25 second 101 primer numbers" stand for? Also one I figured out there is 25 prime numbers between 2 and 101 exclusive why do I plug in 1 for n? Which I did because of my gutfeeling but I rather have a mathematical explanation



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Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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22 Mar 2018, 00:42
How is this question important?
No matter what n is, even or odd, the answer is always 0. :/
It takes 10 seconds to just look at the powers to be consecutive and answer this question. What was the entire point of the second sum of prime numbers to be 110? :/




Re: Math Revolution and GMAT Club Contest! If x=1 and n is the sum of the
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