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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =

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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post 11 Aug 2019, 04:33
1
1
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A
B
C
D
E

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Question Stats:

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If \(x = -1\) then \(x^4 - x^3 + x^2 - x^1 + x^0 =\)

A. -3

B. -2

C. 3

D. 4

E. 5

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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post 11 Aug 2019, 06:17
3
SajjadAhmad wrote:
If \(x = -1\) then \(x^4 - x^3 - x^2 - x^1 - x^0 =\)

A. -3

B. -2

C. 3

D. 4

E. 5

Am I wrong?
Each number to the power of 0 equals 1.
So -1 ^0= 1
So , -1^4 - (-1^3)-(-1^2)-(-1)-1=1
But there is not among options.

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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post 12 Aug 2019, 00:53
My answer is coming as 1 but the in option not given.
My approach-

x = -1
then x^4 - x^3 - x^2 - x^1 - x^0

= (-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1+1-1+1-1
=1
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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post 12 Aug 2019, 01:38
1
As the value of X=-1, so even power will be positive so the solution is:
(-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1-(-1)-(1)-(-1)-(-1)
=1+1-1+1+1
=3
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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post Updated on: 16 Aug 2019, 10:55
1
meht wrote:
As the value of X=-1, so even power will be positive so the solution is:
(-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1-(-1)-(1)-(-1)-(-1)
=1+1-1+1+1
=3


meht \((-1)^0=1\) and NOT -1 so you should get 1+1-1+1-1=1
SajjadAhmad: Can you please check the options else please provide the OE. Thanks
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Originally posted by stne on 16 Aug 2019, 10:37.
Last edited by stne on 16 Aug 2019, 10:55, edited 1 time in total.
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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post 16 Aug 2019, 10:48
Thank you! edited, kindly refresh the page.

stne wrote:
meht wrote:
As the value of X=-1, so even power will be positive so the solution is:
(-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1-(-1)-(1)-(-1)-(-1)
=1+1-1+1+1
=3


meht \((-1)^0=1\) and NOT -1 so you should get 1+1+-1+1-1=1
SajjadAhmad: Can you please check the options else please provide the OE. Thanks

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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post Updated on: 10 Sep 2019, 04:29
1
\(x^4 - x^3 - x^2 - x^1 + x^0\)
\(= (-1)^4-(-1)^3-(-1)^2-(-1)^1+(-1)^0\)
\(= 1 + 1 + 1 + 1 + 1 = 5\)

Answer is (E)

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Originally posted by chondro48 on 16 Aug 2019, 16:40.
Last edited by chondro48 on 10 Sep 2019, 04:29, edited 2 times in total.
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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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New post 16 Aug 2019, 17:56
SajjadAhmad wrote:
If \(x = -1\) then \(x^4 - x^3 + x^2 - x^1 + x^0 =\)

A. -3

B. -2

C. 3

D. 4

E. 5


1+1+1+1+1=5

IMO E

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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =   [#permalink] 16 Aug 2019, 17:56

If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =

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