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# If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =

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Joined: 02 Nov 2016
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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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11 Aug 2019, 05:33
1
1
00:00

Difficulty:

15% (low)

Question Stats:

57% (00:42) correct 43% (01:33) wrong based on 35 sessions

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If $$x = -1$$ then $$x^4 - x^3 + x^2 - x^1 + x^0 =$$

A. -3

B. -2

C. 3

D. 4

E. 5

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Joined: 29 Jun 2019
Posts: 180
Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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11 Aug 2019, 07:17
3
If $$x = -1$$ then $$x^4 - x^3 - x^2 - x^1 - x^0 =$$

A. -3

B. -2

C. 3

D. 4

E. 5

Am I wrong?
Each number to the power of 0 equals 1.
So -1 ^0= 1
So , -1^4 - (-1^3)-(-1^2)-(-1)-1=1
But there is not among options.

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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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12 Aug 2019, 01:53
My answer is coming as 1 but the in option not given.
My approach-

x = -1
then x^4 - x^3 - x^2 - x^1 - x^0

= (-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1+1-1+1-1
=1
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Joined: 12 Aug 2019
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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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12 Aug 2019, 02:38
1
As the value of X=-1, so even power will be positive so the solution is:
(-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1-(-1)-(1)-(-1)-(-1)
=1+1-1+1+1
=3
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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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Updated on: 16 Aug 2019, 11:55
1
meht wrote:
As the value of X=-1, so even power will be positive so the solution is:
(-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1-(-1)-(1)-(-1)-(-1)
=1+1-1+1+1
=3

meht $$(-1)^0=1$$ and NOT -1 so you should get 1+1-1+1-1=1
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- Stne

Originally posted by stne on 16 Aug 2019, 11:37.
Last edited by stne on 16 Aug 2019, 11:55, edited 1 time in total.
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GPA: 3.39
Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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16 Aug 2019, 11:48
Thank you! edited, kindly refresh the page.

stne wrote:
meht wrote:
As the value of X=-1, so even power will be positive so the solution is:
(-1)^4-(-1)^3-(-1)^2-(-1)^1-(-1)^0
=1-(-1)-(1)-(-1)-(-1)
=1+1-1+1+1
=3

meht $$(-1)^0=1$$ and NOT -1 so you should get 1+1+-1+1-1=1

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If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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Updated on: 17 Aug 2019, 05:45
1

$$x^4 - x^3 - x^2 - x^1 + x^0$$
$$= (-1)^4-(-1)^3-(-1)^2-(-1)^1+(-1)^0$$
$$= 1 + 1 + 1 + 1 + 1 = 5$$

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Originally posted by chondro48 on 16 Aug 2019, 17:40.
Last edited by chondro48 on 17 Aug 2019, 05:45, edited 1 time in total.
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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =  [#permalink]

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16 Aug 2019, 18:56
If $$x = -1$$ then $$x^4 - x^3 + x^2 - x^1 + x^0 =$$

A. -3

B. -2

C. 3

D. 4

E. 5

1+1+1+1+1=5

IMO E

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Re: If x = -1 then x^4 - x^3 - x^2 - x^1 - x^0 =   [#permalink] 16 Aug 2019, 18:56
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