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x^2 + 6x > 27
x^2 + 6x - 27 > 0
(x+9) (x-3) > 0

x > -9
x > 3

when plotting on number line
we get x> 3 or x< -9
option D
ExpertsGlobal5
If x^2 + 6x > 27, which of the following specifies all the possible values of x ?

A. x > 3
B. x < –9
C. –9 < x < 3
D. x > 3 or x < –9
E. x > 9 or x < –3

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If x^2 + 6x > 27, which of the following specifies all the possible values of x?

x^2 + 6x > 27

x^2 + 6x - 27 > 0

(x + 9)(x - 3) > 0

For (x + 9)(x - 3) to be positive, it must be that either both (x + 9) and (x - 3) are positive or both are negative.

(x + 9) = 0 at -9. Below -9, (x + 9) is negative. Above -9, it's positive.

(x - 3) = 0 at 3. Below 3, (x - 3) is negative. Above 3, it's positive.

So, the signs of the two factors work as follows:

- - (-9) + - (3) + +

We see that both factors are negative below -9 and both are positive above 3.

Thus, x > 3 or x < –9.

A. x > 3
B. x < –9
C. –9 < x < 3
D. x > 3 or x < –9
E. x > 9 or x < –3


Correct answer: D
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ExpertsGlobal5
If x^2 + 6x > 27, which of the following specifies all the possible values of x ?

A. x > 3
B. x < –9
C. –9 < x < 3
D. x > 3 or x < –9
E. x > 9 or x < –3

D is the correct answer choice.

Video explanation:

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