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21 Aug 2019, 02:06
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Question Stats:
65% (00:36) correct
35%
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If \(x^{-3} = -\frac{1}{8}\), then \(x^{-2}\) is equal to
A. -4
B. -2
C. -1/4
D. 1/4
E. 4
A. -4
B. -2
C. -1/4
D. 1/4
E. 4
21 Aug 2019, 02:43
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Bunuel
If \(x^{-3} = -\frac{1}{8}\), then \(x^{-2}\) is equal to
A. -4
B. -2
C. -1/4
D. 1/4
E. 4
A. -4
B. -2
C. -1/4
D. 1/4
E. 4
from given infor
\(x^{-3} = -\frac{1}{8}\)
x=2 so \(x^{-2}\) ; 1/4
IMO D
21 Aug 2019, 03:27
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Bunuel
If \(x^{-3} = -\frac{1}{8}\), then \(x^{-2}\) is equal to
A. -4
B. -2
C. -1/4
D. 1/4
E. 4
A. -4
B. -2
C. -1/4
D. 1/4
E. 4
\((x^{-3})^{2/3} =( -\frac{1}{8})^{2/3}\)
Or, \(x^{-2}= ({(-1/2)^3})^{2/3}\)
Or, \(x^{-2}= (-1/2)^2\)
Or, x=1/4
Ans. (D)
