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If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ?

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pmklings
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If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ? [#permalink] New post   Updated on: 06 Mar 2023, 03:00
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If \(x≠3\) and \(\frac{(x^2 - 9)}{2y}\) = \(\frac{(x - 3)}{4}\), then in terms of \(y, x =\) ?

A. \(\frac{(y - 6)}{2}\)
B. \(\frac{(y - 3)}{2}\)
C. \(y - 3\)
D. \(y - 6\)
E. \(\frac{(y + 6)}{2}\)
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A

Originally posted by pmklings on 16 Sep 2015, 23:05.
Last edited by Bunuel on 06 Mar 2023, 03:00, edited 4 times in total.
Renamed the topic and edited the question.
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Re: If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ? [#permalink] New post   16 Sep 2015, 23:43
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pmklings wrote:
If x≠3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ?

A. (y - 6)/2
B. (y - 3)/2
C. y - 3
D. y - 6
E. (y + 6)/2



\(\frac{(x^2 - 9)}{(2y)} = \frac{(x - 3)}{4}\);

\(\frac{(x - 3)(x+3)}{(2y)} = \frac{(x - 3)}{4}\);

\(\frac{(x+3)}{(2y)} = \frac{1}{4}\);

\(x+3=\frac{y}{2}\);

\(x=\frac{(y-6)}{2}\).

Answer: A.

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Re: If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ? [#permalink] New post   16 Sep 2015, 23:48
pmklings wrote:
If x≠3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ?

A. (y - 6)/2
B. (y - 3)/2
C. y - 3
D. y - 6
E. (y + 6)/2



(x^2 - 9)/(2y) = (x - 3)/4

4(x^2-9)=2y(x-3)
2.2(x^2 - 3^2)/ 2=y(x-3)
2(x+3)(x-3)/(x-3)=y
2(x+3)=y
2x+6=y
2x=y-6
y=(y-6)/2
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Re: If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ? [#permalink] New post   17 Sep 2015, 01:06
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.


If x≠3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ?

A. (y - 6)/2
B. (y - 3)/2
C. y - 3
D. y - 6
E. (y + 6)/2

Since (x^2 – 9)=(x-3)(x+3) the original equation can be changed into 4*(x-3)(x+3) = 2y *(x-3).
By cancelling 2(x-3) (we can do it because x≠3) we get :
2*(x+3)=y.
So x=(y-6)/2. So the answer is A).
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Re: If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ? [#permalink] New post   14 Sep 2023, 17:09
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If x3 and (x^2 - 9)/(2y) = (x - 3)/4, then in terms of y, x = ? [#permalink]
14 Sep 2023, 17:09
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