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If x = 3 and y = 6, is y > nx + k?

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If x = 3 and y = 6, is y > nx + k?  [#permalink]

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New post 23 Mar 2017, 00:30
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If x = 3 and y = 6, is y > nx + k ?

(1) n = 5

(2) k = -10

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If x = 3 and y = 6, is y > nx + k?  [#permalink]

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New post Updated on: 26 Mar 2017, 00:05
If x = 3 and y = 6, is y > nx + k ?

Question asks if 6 > 3n + k

Statement (1) n = 5

6 > 3n + k

Replacing value of n

6 > 15 + K , Since we do not know the value of K, this statement is not sufficient.


Statement (2) k = -10


6 > 3n + k

Replacing value of K

6 > 3n - 10

16 > 3n , Since we do not know the value of n, this statement is not sufficient.

Combining both statements

16 > 3n

Replacing value of n

16 > 15, Hence both statements are sufficient.

Originally posted by quantumliner on 24 Mar 2017, 09:58.
Last edited by quantumliner on 26 Mar 2017, 00:05, edited 1 time in total.
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If x = 3 and y = 6, is y > nx + k?  [#permalink]

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New post Updated on: 26 Mar 2017, 00:26
Could someone explain why statement (1) is not sufficient on its own?

y > nx + k
6 > (5)(3) + k
6 - 15 > k
-9 > k

Testing values of k=-10, k=-11
6>5(3) + k
6>5(3) -10
6>5
AND
6>5(3)-11
6>4

And so on. So statement (1) appears to be sufficient on its own. Bunuel, could you explain where I'm going wrong please?

Originally posted by Push2018 on 25 Mar 2017, 23:20.
Last edited by Push2018 on 26 Mar 2017, 00:26, edited 1 time in total.
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Re: If x = 3 and y = 6, is y > nx + k?  [#permalink]

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New post 26 Mar 2017, 00:12
GoInsead

In Statement 1, you have resolved the equation to -9 > k. Now since from statement 1, you do no know the value of K, you do not know if K is less than -9. Hence statement 1 is not sufficient.

Similarly, when you plug in the value on k = -10 in the equation 6 > 3n + k, it resolves to 16 > 3n , Since we do not know the value of n, this statement is not sufficient.

Hence using both statements together, will help in solving. Therefore Answer is C.

Does it help?
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Re: If x = 3 and y = 6, is y > nx + k?  [#permalink]

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New post 26 Mar 2017, 00:34
quantumliner wrote:
GoInsead

In Statement 1, you have resolved the equation to -9 > k. Now since from statement 1, you do no know the value of K, you do not know if K is less than -9. Hence statement 1 is not sufficient.

Similarly, when you plug in the value on k = -10 in the equation 6 > 3n + k, it resolves to 16 > 3n , Since we do not know the value of n, this statement is not sufficient.

Hence using both statements together, will help in solving. Therefore Answer is C.

Does it help?


I guess, my question is:

I used the information in statement (1) to find out what k could possibly be with that value of n. For values -9 > k, it appears y>nx + k is ALWAYS true. Hence, I concluded statement (1) is sufficient. What part of my process is flawed?
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Re: If x = 3 and y = 6, is y > nx + k? &nbs [#permalink] 26 Mar 2017, 00:34
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