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If x = 3 and y = 6, is y > nx + k ? (1) n = 5 (2) k = -10

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 51215
If x = 3 and y = 6, is y > nx + k ? (1) n = 5 (2) k = -10  [#permalink]

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New post 18 Jul 2018, 23:19
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

94% (00:52) correct 6% (01:01) wrong based on 16 sessions

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Joined: 22 May 2017
Posts: 1473
Concentration: Nonprofit
GPA: 4
WE: Engineering (Computer Software)
Re: If x = 3 and y = 6, is y > nx + k ? (1) n = 5 (2) k = -10  [#permalink]

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New post 18 Jul 2018, 23:30
To find whether y > nx + k ?

x = 3 and y = 6

=> we need to find whether 6 > 3n + k ?

Statement 1

n = 5

=> 6 > 3*5 + k ?

=> 6 > 15 + k ?

We don't know the value of k. So we cannot find a unique answer for above expression

Statement 2

k = -10

=> 6 > 3n - 10 ?

We don't know the value of n. So we cannot find a unique answer for above expression

Combining statements 1 and 2

=> 6 > 3n + k ?

=> 6 > 15 - 10 ?

=> 6 > 5 TRUE

Hence option C
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Re: If x = 3 and y = 6, is y > nx + k ? (1) n = 5 (2) k = -10  [#permalink]

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New post 19 Jul 2018, 01:16
Bunuel wrote:
If x = 3 and y = 6, is y > nx + k ?


y > nx + k
6 > 3n + k

(1) n = 5
No value of k, Insufficient

(2) k = -10
No value of n, Insufficient

Combining 1 & 2:
6 > 15 - 10
6 > 5
Sufficient

Hence, C.
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Re: If x = 3 and y = 6, is y > nx + k ? (1) n = 5 (2) k = -10 &nbs [#permalink] 19 Jul 2018, 01:16
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If x = 3 and y = 6, is y > nx + k ? (1) n = 5 (2) k = -10

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