chloe2m
Bunuel
Bunuel
If \(x > 0\) and \(x^{(3*x^{12})}=4\), what is the value of \(x\) ?
A. \(\sqrt[12]{2}\)
B. \(\sqrt[6]{2}\)
C. \(\sqrt[3]{2}\)
D. \(\sqrt{3}\)
E. \(\sqrt{2}\)
Official Solution:If \(x > 0\) and \(x^{(3*x^{12})}=4\), what is the value of \(x\) ? A. \(\sqrt[12]{2}\)
B. \(\sqrt[6]{2}\)
C. \(\sqrt[3]{2}\)
D. \(\sqrt{3}\)
E. \(\sqrt{2}\)
\(x^{(3*x^{12})}=4\);
Take to the fourth power:
\((x^{(3*x^{12})})^4=4^4\);
\(x^{(12*x^{12})}=4^4\);
\((x^{12})^{(x^{12})} =4^4\);
\(x^{12}=4=2^2\);
\(x=(2^2)^{(\frac{1}{12})}\);
\(x=2^{(\frac{1}{6})}\);
\(x=\sqrt[6]{2}\)
Answer: B
Hi
Bunuel !
Could you please explain how you go from this line to the other:
\((x^{12})^{(x^{12})} =4^4\);
\(x^{12}=4=2^2\);
And from this line to this one:
\(x^{12}=4=2^2\);
\(x=(2^2)^{(\frac{1}{12})}\);
Thank you for your help

In the equation \((x^{12})^{(x^{12})} =4^4\), observe that on the left side, the expression \(x^{12}\) is repeated, just as the number 4 is repeated on the right side. Therefore, we can infer \(x^{12}=4\).
In the next part, where \(x^{12}=2^2\), to isolate x, we take the 12th root of both sides, which gives \(x=(2^2)^{(\frac{1}{12})}\).
Hope it's clear.