AnisMURR
If \(x^3 < x^2\), is \(x > 0 ?\)
A. \(|x|<1\)
B. \(x > x^2\)
\(x^3 < x^2........x^3-x^2<0......x^2(x-1)<0\)
x^2 will always be non negative, therefore x-1<0 or x<1...
So we know X<1, we have to check if it is between 0 and 1 or not..
1) |x|<1...
This can be written as -1<X<1..
So, we can not have a definite answer...
2) X>x^2...
If the number is negative, it's square will be positive and hence square will always be greater than the number itself.
Therefore, the number is not negative and will be between 0 and 1..
Sufficient..
Also \(x>x^2.....X(1-x)>0\)...
Two cases..
if x is negative, 1-x too has to be negative. But 1-x will always be positive if x<0...
So x has to be positive.. and 1-x>0...X<1
B
But i have a small thing to mention. It doesn't affect your solution but.
If \(x^3 < x^2\) this does not mean that \(x<1\) because when\(x = 0\) both quantities are equal.