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Within few seconds, I think it is D because you have 3000/6001 --> a bit less but almost equal to 1/2. C was tricky but I think it is too much below the average of 10.5
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Re: If x > 3000, then the value of (x)/(2x+1) is closest to? [#permalink]

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27 Dec 2013, 11:20

cloaked_vessel wrote:

If x > 3000, then the value of (x)/(2x+1) is closest to?

A 1/6 B 1/3 C 10/21 D 1/2 E 3/2

I assumed that we could do this:

3001/(2*3001) +1 = 1/(2*1) + 1 ----> answer B

Why can we not "short" the numerator and the value of x in the denominator? Of course, I understand 3001/6003 is almost 1/2 but IMO my reasoning for B should work.. What am I missing?

Re: If x > 3000, then the value of (x)/(2x+1) is closest to? [#permalink]

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28 Dec 2013, 03:37

2

aeglorre wrote:

cloaked_vessel wrote:

If x > 3000, then the value of (x)/(2x+1) is closest to?

A 1/6 B 1/3 C 10/21 D 1/2 E 3/2

I assumed that we could do this:

3001/(2*3001) +1 = 1/(2*1) + 1 ----> answer B

Why can we not "short" the numerator and the value of x in the denominator? Of course, I understand 3001/6003 is almost 1/2 but IMO my reasoning for B should work.. What am I missing?

\(\frac{x}{2x+1}\) does not equal to \(\frac{1}{2+1}\). You cannot reduce numerator and only one term of the denominator by x.