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# If x^a = 2, x^b = 3 and x^c = 6 then x^(3a + b - 2c) = ?

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Re: If x^a = 2, x^b = 3 and x^c = 6 then x^(3a + b - 2c) = ? [#permalink]
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Re: If x^a = 2, x^b = 3 and x^c = 6 then x^(3a + b - 2c) = ? [#permalink]