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# If x and y are consecutive negative integers, is x greater

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Joined: 20 Nov 2009
Posts: 128
If x and y are consecutive negative integers, is x greater  [#permalink]

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Updated on: 04 Aug 2010, 22:18
6
00:00

Difficulty:

25% (medium)

Question Stats:

76% (01:26) correct 24% (01:48) wrong based on 123 sessions

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If x and y are consecutive negative integers, is x greater than y?

(1) x + 1 and y – 1 are consecutive negative integers.
(2) x is an even integer.

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But there’s something in me that just keeps going on. I think it has something to do with tomorrow, that there is always one, and that everything can change when it comes.
http://aimingformba.blogspot.com

Originally posted by aiming4mba on 04 Aug 2010, 21:58.
Last edited by aiming4mba on 04 Aug 2010, 22:18, edited 1 time in total.
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04 Aug 2010, 22:51
1
aiming4mba wrote:
If x and y are consecutive negative integers, is x greater than y?
a. x + 1 and y – 1 are consecutive negative integers.
b. x is an even integer.

$$x$$ and $$y$$ are consecutive integers means that either:
$$y=x+1$$ (for example $$x=-5$$ and $$y=-4$$), in this case $$x<y$$;
OR:
$$x=y+1$$ (for example $$x=-5$$ and $$y=-6$$), in this case $$x>y$$.

So the we should determine which case we have.

(1) $$x+1$$ and $$y-1$$ are consecutive negative integers --> again either $$x+1=(y-1)+1$$ --> $$x+1=y$$ (first case so $$x<y$$) or $$y-1=(x+1)+1$$ --> $$y=x+3$$, which is not possible as $$x$$ and $$y$$ are consecutive integers (difference between two consecutive integers can not equal to 3). So only first case is possible: $$x<y$$. Sufficient.

(2) $$x$$ is an even integer. Clearly insufficient.

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Re: If x and y are consecutive negative integers, is x greater  [#permalink]

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13 Sep 2018, 03:10
Hello from the GMAT Club BumpBot!

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Re: If x and y are consecutive negative integers, is x greater &nbs [#permalink] 13 Sep 2018, 03:10
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