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hi
can someone please provide the explanation for this question? I didn't understand the given solution
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If xx and yy are integers and 7x+1−7x−13=(2y)(496)7x+1−7x−13=(2y)(496) what is the value of xyxy?
solution
(7^(x+1)-7^(x-1))/3=2^y(49)^6
=7^(x-1)(49-1)/3==2^y(49)^6
=7^(x-1)(48)/3=2^y(49)^6
=7^(x-1)(16)=2^y(49)^6
=here by comparing both sides
y=4,x-1=12
y=4,x=13
xy=52
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GMATNinja - I think you guys created this question for the Ukrain marathon but I cannot get to make headwind with this one, is there any solution? The posted solution are all over the place, I wonder if this question is correct, thanks!
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IN2MBB2PE
GMATNinja - I think you guys created this question for the Ukrain marathon but I cannot get to make headwind with this one, is there any solution? The posted solution are all over the place, I wonder if this question is correct, thanks!
I think it's hard to read explanations to exponent questions when they're typed, so here you go:
Attachment:
IMG-6549.jpg
IMG-6549.jpg [ 2.25 MiB | Viewed 3921 times ]
The key is factoring in that very first step. It doesn't FEEL quite right, but think about what you do when you factor something simpler, like (x^8 + x^6). You'd factor out the smaller of the two terms, right?

Same thing here. Once you recognize how to factor out the 7^(x-1), the whole question gets easier quickly.

I hope that helps!
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how did we get 7^x-1 . 7^2 -1 ?
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Zainali385
how did we get 7^x-1 . 7^2 -1 ?



Express \(7^{(x + 1)}\) as \(7^2*7^{(x - 1)}\):

\(7^{(x + 1)} - 7^{(x - 1)} =\\
\\
= 7^2*7^{(x - 1)} - 7^{(x - 1)} = \\
\\
= 7^{(x - 1)}(7^2 - 1) = \)

Hope it's clear.
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