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If x and y are integers, and w = x^2y + x + 3y, which of the following

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Kudos [?]: 135655 [0], given: 12705

If x and y are integers, and w = x^2y + x + 3y, which of the following [#permalink]

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New post 20 Nov 2017, 10:51
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A
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C
D
E

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Question Stats:

38% (01:11) correct 62% (02:37) wrong based on 45 sessions

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If x and y are integers, and \(w = x^2y + x + 3y\), which of the following statements must be true?

I. If w is even, then x must be even.
II. If x is odd, then w must be odd.
III. If y is odd, then w must be odd.

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II and III
[Reveal] Spoiler: OA

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Kudos [?]: 135655 [0], given: 12705

Expert Post
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Joined: 02 Aug 2009
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Kudos [?]: 6128 [0], given: 121

If x and y are integers, and w = x^2y + x + 3y, which of the following [#permalink]

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New post 21 Nov 2017, 07:43
Bunuel wrote:
If x and y are integers, and \(w = x^2y + x + 3y\), which of the following statements must be true?

I. If w is even, then x must be even.
II. If x is odd, then w must be odd.
III. If y is odd, then w must be odd.

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II and III



Actually I and II can be derived from each other if it were a CR question..
I. If w is even, then x must be even..... MEANS... If x is NOT even, w is NOT even ... MEANS if x is odd, w is odd :- SAME as II
so our answer must have BOTH I and Ii.. ONLY C and E are left

But let's solve ..

Ofcourse many ways to solve but just to understand the logic behind it....

\(w = x^2y + x + 3y\)
there are TWO terms, x and 3y , which contain only one of the two variable AND 1 term containing both variable and that too as a product

1) Therefore, if BOTH the variables x and y are opposite that is one odd and one even
a) the term containing both variables will be EVEN as it will be product of E*O
b) the oher terms will be one E and other O
so SUM = w = E+O+E = O

2) if BOTH the variables x and y are SAME
a) ALL the terms will be EVEN if both are even so SUM= w = E+E+E = E
b) ALL the terms will be ODD if both are odd so SUM = w = O+O+O = O

conclusion
if both x and y are EVEN, w is EVEN or, else, w is ODD

let's see the choices...

I. If w is even, then x must be even.
Refer 2(a), w is even only when both x and y are even....TRUE

II. If x is odd, then w must be odd.
refer 1 and 2(b), when x is odd, w is ODD....TRUE

III. If y is odd, then w must be odd.
Again refer the conclusion or 1 and 2(b), y is ODD means w is ODD....TRUE

E all three true
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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

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If x and y are integers, and w = x^2y + x + 3y, which of the following [#permalink]

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New post 21 Nov 2017, 07:45
Bunuel wrote:
If x and y are integers, and \(w = x^2y + x + 3y\), which of the following statements must be true?

I. If w is even, then x must be even.
II. If x is odd, then w must be odd.
III. If y is odd, then w must be odd.

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II and III


A simple glance at the question will indicate that easy number substitution for \(x\) & \(y\) can solve this question

as \(w = x^2y + x + 3y\). So we can have different scenarios for \(x\) & \(y\)

1) \(x=0 (even)\), \(y=1 (odd)\) ; \(w=3 (odd)\)

2) \(x=0 (even)\), \(y=0 (even)\) ; \(w=0 (even)\)

3) \(x=1 (odd)\), \(y=0 (even)\) ; \(w=1 (odd)\)

4) \(x=1 (odd)\), \(y=1 (odd)\) ; \(w=5 (odd)\)

Now -

I. If \(w\) is even, then \(x\) must be even - Always True

II. If \(x\) is odd, then \(w\) must be odd. - Always True

III. If \(y\) is odd, then \(w\) must be odd. - Always True

Option E

Kudos [?]: 309 [0], given: 39

If x and y are integers, and w = x^2y + x + 3y, which of the following   [#permalink] 21 Nov 2017, 07:45
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If x and y are integers, and w = x^2y + x + 3y, which of the following

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