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If x and y are integers, what is the ratio of 3y to x?

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If x and y are integers, what is the ratio of 3y to x? [#permalink]

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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 01 Jun 2016, 04:15
1. x^3/y^3 = 27/8 --> y/x = 2/3 --> 3y/x = 2 -- sufficient !!
2. x^2/y^2 = 9/4 --> y/x = + - 2/ + - 3 (4 possible values) --- insufficient !!

A

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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 01 Jun 2016, 06:31
Do we exclude the option that both x & y are 0 because then in the ratio equation we would be dividing by 0?
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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 02 Jun 2016, 00:03
CounterSniper wrote:
1. x^3/y^3 = 27/8 --> y/x = 2/3 --> 3y/x = 2 -- sufficient !!
2. x^2/y^2 = 9/4 --> y/x = + - 2/ + - 3 (4 possible values) --- insufficient !!

A



I think it should be D-in statement 2, whether we take values as 3,2 OR -3,-2, the ration remains the same.

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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 02 Jun 2016, 11:31
Bunuel wrote:
If x and y are nonzero integers, what is the ratio of 3y to x?

(1) 8x^3 = 27y^3
(2) 4x^2 = 9y^2


We need to find 3y/x

(1) 8x^3 = 27y^3
x= (27y^3/8)^1/3
x= 3y/2

Since we have odd power, sign of x and y will be same as of x^3 and y^3

By putting value of x in 3y/x, we will get the answer

(2) 4x^2 = 9y^2

x= (9y^2/4) ^1/2

Sign of x and y may or may not be same as x^2 and y^2. Hence we can not find the ratio. Not sufficient

IMO, A is the answer
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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 02 Jun 2016, 11:33
fantaisie wrote:
Do we exclude the option that both x & y are 0 because then in the ratio equation we would be dividing by 0?


Please note that its given that x and y are non zero integers :)
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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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KS15 wrote:
CounterSniper wrote:
1. x^3/y^3 = 27/8 --> y/x = 2/3 --> 3y/x = 2 -- sufficient !!
2. x^2/y^2 = 9/4 --> y/x = + - 2/ + - 3 (4 possible values) --- insufficient !!

A



I think it should be D-in statement 2, whether we take values as 3,2 OR -3,-2, the ration remains the same.


What if it is -3, 2 or 3 -2 (we can have the +ve ratio or -ve ratio). IMO statement 2 is not sufficient. What do you say?
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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 02 Jun 2016, 11:38
Divyadisha wrote:
KS15 wrote:
CounterSniper wrote:
1. x^3/y^3 = 27/8 --> y/x = 2/3 --> 3y/x = 2 -- sufficient !!
2. x^2/y^2 = 9/4 --> y/x = + - 2/ + - 3 (4 possible values) --- insufficient !!

A



I think it should be D-in statement 2, whether we take values as 3,2 OR -3,-2, the ration remains the same.


What if it is -3, 2 or 3 -2 (we can have the +ve ratio or -ve ratio). IMO statement 2 is not sufficient. What do you say?



Agree it should be A-my bad-I must be inattentive to miss such a simple one.Thanks

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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 02 Jun 2016, 11:44
I think it should be D-in statement 2, whether we take values as 3,2 OR -3,-2, the ration remains the same.[/quote]

What if it is -3, 2 or 3 -2 (we can have the +ve ratio or -ve ratio). IMO statement 2 is not sufficient. What do you say?[/quote]


Agree it should be A-my bad-I must be inattentive to miss such a simple one.Thanks[/quote]

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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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New post 02 Jun 2016, 21:34
If x and y are nonzero integers, what is the ratio of 3y to x?

(1) 8x^3 = 27y^3
(2) 4x^2 = 9y^2

Statement 1-->Sufficient. As given,both x and y are nonzero integers,so both x and y should have same sign( Either both should be positive or both could be negative). In either case 2x = 3y which leads to 3y/x = 2.

Statement 2-->Not Sufficient. (2x-3y)(2x+3y) = 0 ,that makes 3y/x = 2 or -2.

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Re: If x and y are integers, what is the ratio of 3y to x? [#permalink]

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Re: If x and y are integers, what is the ratio of 3y to x?   [#permalink] 21 Sep 2017, 09:58
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