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Re: If x and y are integers, what is the value of 2x^6y - 4 ? [#permalink]
is the question: (2x)^(6y-4)?

then the ans should be E
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Re: If x and y are integers, what is the value of 2x^6y - 4 ? [#permalink]
banksy wrote:
If x and y are integers, what is the value of 2x^6y - 4 ?
(1) x^2y = 16
(2) x^y = 4



i am a bit dumb these days but i think the answer of this data question is E

here is what i solved.
statement 1: x^2y=16=4^2 =2^4
so x could be 4 and y could be 1
or x could be 2 and y could be 2
insufficient
statement 2: x^y=4 =2^2=4^1
x could be 2 and y could be 2
x could be 4 and y could be 1
the same as statement 1 so insufficient.
1+2 cant conclude anything because the question doesnt say if x and y are two different integer thus insufficient
E
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Re: If x and y are integers, what is the value of 2x^6y - 4 ? [#permalink]
Please use brackets where ever possible . From the way the question is laid out , its hard to figure out whether
you meant 2(x^6)y-4 or 2(x^(6y))-4



If its 2(x^(6y))-4,

1. Sufficient

x^(2y) = 16
=> x^(6y) = 16^3 . This is sufficient to solve the expression.

2. Sufficient

x^y = 4 = > x^(6y) = 4^6. This is sufficient to solve the expression.

Answer is D.



banksy wrote:
If x and y are integers, what is the value of 2x^6y - 4 ?
(1) x^2y = 16
(2) x^y = 4
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Re: If x and y are integers, what is the value of 2x^6y - 4 ? [#permalink]
has to be D.
btw a very poor worded question :twisted: :twisted: :twisted: :twisted:



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