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19 Jan 2015, 05:46
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
62% (02:24) correct
38%
(02:30)
wrong
based on 79
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If x and y are positive, does (x-2)(y-3)=6?
(1) 3x=y(x-2)
(2) (x-8)(y^2+5) =0
(1) 3x=y(x-2)
(2) (x-8)(y^2+5) =0
19 Jan 2015, 08:20
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Bunuel
Hi,
Answer should be A.
Statement 1: According to the given equation, y = 3x/(x-2). Repalcing y with 3x/(x-2) in the equation (x-2)(y-3) gives 6. Sufficient.
Statement 2: Only solution possible to this equation is x = 8, so not sufficient.
19 Jan 2015, 12:43
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Bunuel
Answer: A
from the stem, question is: xy-2y-3x+6=6? or 3x = y(x-2)
from 1: directly gives the answer, sufficient
from 2: (x-8)(y^2+5) = 0, implies x= 8, no info on y and y can be any value, so NSF.
