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06 Jan 2023, 09:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:59) correct
36%
(02:32)
wrong
based on 105
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are positive integers and x is odd, is xy even?
(1) x^3*y = 6a^3 + 23 where a is a positive integer
(2) x^2 + y = 3k + 7 where k is a positive integer
(1) x^3*y = 6a^3 + 23 where a is a positive integer
(2) x^2 + y = 3k + 7 where k is a positive integer
06 Jan 2023, 10:11
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Posted from my mobile device
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File comment: Option A is the answer
IMG_20230106_224017__01.jpg [ 2.93 MiB | Viewed 1601 times ]
09 Feb 2025, 10:47
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x^3*y be better written as (x^3)*y to save the confusion. If x^3*y is imterpreted as x^(3*y), then the answer is E.
But yeah, I know BODMAS, so never mind !!
But yeah, I know BODMAS, so never mind !!
