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17 Aug 2016, 01:56
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:19) correct
25%
(01:46)
wrong
based on 103
sessions
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If x and y are positive integers and y ≠ 1, then xy(y −1) is
A. Always even
B. Always odd
C. Odd only when x is odd
D. Even only when y is even
E. Odd only when xy is odd
A. Always even
B. Always odd
C. Odd only when x is odd
D. Even only when y is even
E. Odd only when xy is odd
17 Aug 2016, 02:27
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Bunuel
Here given condition is x and y are positive integers and y ≠ 1, then xy(y −1) ?
As per the table result we always get even result..option A.
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18 Aug 2016, 17:13
Kudos
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Expression is xy(y-1). We can ignore x and only work with y.
If y = even -> entire expression is even since anything multiplied by even is even
If y = odd, y-1 -> even -> entire expression is even since anything multiplied by even is even
Hence, entire expression will always be even.
Answer (A).
If y = even -> entire expression is even since anything multiplied by even is even
If y = odd, y-1 -> even -> entire expression is even since anything multiplied by even is even
Hence, entire expression will always be even.
Answer (A).
