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13 Feb 2019, 00:33
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If x and y are positive integers, is \(\frac{x}{y} > 1\)?
(1) \(x + 3 = y\)
(2) \(\frac{x + 5}{y} > 1\)
(1) \(x + 3 = y\)
(2) \(\frac{x + 5}{y} > 1\)
13 Feb 2019, 06:33
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Bunuel
If x and y are positive integers, is \(\frac{x}{y} > 1\)?
(1) \(x + 3 = y\)
(2) \(\frac{x + 5}{y} > 1\)
(1) \(x + 3 = y\)
(2) \(\frac{x + 5}{y} > 1\)
x/y>1
#1
x+3=y
so it means that y is >x always and x/y wont be >1 sufficient
#2
x+5/y>1
test with x = 1 and y = 3 ; 1/3 ; sufficient
again x=5 , y=2 relation is not sufficient
IMO A
KanishkM
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13 Feb 2019, 07:20
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Bunuel
If x and y are positive integers, is \(\frac{x}{y} > 1\)?
(1) \(x + 3 = y\)
(2) \(\frac{x + 5}{y} > 1\)
(1) \(x + 3 = y\)
(2) \(\frac{x + 5}{y} > 1\)
x & y are +ive Integers
To find is x > y
from 1, x + 3 = y
y will be always > x, This will always be a No.
Sufficient
from 2, x+5 > y
x > y - 5
x = 4, y = 2 , 4 > 2, Yes
x = 1, y = 1, 1 > 1 No
Not Sufficient
A
