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If x and y are prime numbers, is y(x-3) odd?

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Joined: 23 Jul 2018
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Re: If x and y are prime numbers, is y(x-3) odd?  [#permalink]

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New post 23 Jul 2018, 09:02
Hey,

Sorry to bring this back up again, but I still do not get why the answer is D and not A

I will just take a look at the second statement, as I do understand why the first Statement is sufficient.

(2) Y<3 => okay because x & y are prime numbers, and Y is less than 3 => y=2
So far so good, now, if we put Y into the equation, the equation will look something like this

2(x-3)

So we know, that X is a prime, Statement 2 would always be sufficient except when X=3
2(3-3)=0
The question stem asks if the outcome for the equation is odd, afaik 0 is neither. So how can the statement be sufficient? What am I not seeing?

Best regards!
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Re: If x and y are prime numbers, is y(x-3) odd?  [#permalink]

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New post 23 Jul 2018, 09:27
Jobish wrote:
Hey,

Sorry to bring this back up again, but I still do not get why the answer is D and not A

I will just take a look at the second statement, as I do understand why the first Statement is sufficient.

(2) Y<3 => okay because x & y are prime numbers, and Y is less than 3 => y=2
So far so good, now, if we put Y into the equation, the equation will look something like this

2(x-3)

So we know, that X is a prime, Statement 2 would always be sufficient except when X=3
2(3-3)=0
The question stem asks if the outcome for the equation is odd, afaik 0 is neither. So how can the statement be sufficient? What am I not seeing?

Best regards!


Note that 0 is an even number, so y(x-3) will be even even if x = 3.

ZERO.

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

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Re: If x and y are prime numbers, is y(x-3) odd? &nbs [#permalink] 23 Jul 2018, 09:27

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