Q comes down to Analyzing the Modulus and the Output/Outcome
(1st) we are told that B = a NON-Zero Integer
Given:
(-)[X] = B
X must also be = a NON-Zero Integer
(2nd)
(-)[X] = B
The OUTPUT of the Modulus [X] must be (+)Pos. since X can NOT be 0
(-)[X] = (-) * (+Pos. Integer Output) = (-)Negative Integer = B
thus, we know for Sure that B must be a (-)Negative Integer
I not only can be true: I must be True
II. X < (-)B
Since we know that B must = (-)Negative Integer:
The Expression (-)B ------> (-) * (-Neg. Integer) = (+)Positive Integer
If the INPUT X into the Modulus is (-)Negative, then we can have a case where ----> X < (-)B
Case: X = (-)5
(-) * [-5] = B
(-) * +5 = B
B = (-)5
and therefore ------> (-)B = (-) * (-5) = +5
X = (-)5 -------- and ------- (-)B = +5
it can be true that: X < (-)B
II can be True
III. X > B
Again, since we know that B must be = (-)Neg. Integer
If the Input X = (+)Pos. Integer, then we can easily Find a Case where X > B
Case:
Given ----> (-) * [X] = B
If X = +2
(-) * [+2] = B
(-) * +2 = B
B = (-)2
X (+2) > B (-2)
III. Can be True
-E-
I, II, and III all can be True