Bunuel wrote:

If X is 60 percent more than Y and Y is 40 percent less than Z, then what percent of Z is X?

(A) 64%

(B) 80%

(C) 96%

(D) 120%

(E) 124%

OA:C

X is 60 percent more than Y.\(X = Y + \frac{60}{100}.Y\)

\(X= \frac{160}{100}.Y\)

\(X= 1.6 Y\) [1]

Y is 40 percent less than Z\(Y= Z - \frac{40}{100}.Z\)

\(Y= \frac{60}{100}.Z\)

\(Y= 0.6.Z\) [2]

What percent of Z is X will be given by \(\frac{X}{Z}.100\)

Putting value of Y from [2] into [1],we get

\(X= 1.6 * 0.6 Z\)

\(\frac{X}{Z}= 1.6 * 0.6\)

\(\frac{X}{Z}*100 =1.6*0.6*100\)

\(\frac{X}{Z}*100=96\)

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