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Bunuel
If x is a non-negative integer such that \(7^{\sqrt{x}}+ 24^{\sqrt{x}} = 25^{\sqrt{x}}\), what is the value of x?


A. 0
B. 1
C. 2
D. 3
E. 4
For convenience sake I will start with \(x = 4\) , as \(\sqrt{4 = 2}\)

So, \(7^{\sqrt{4}}+ 24^{\sqrt{4}} = 25^{\sqrt{4}}\)

Or, \(7^2+ 24^2 = 25^2\)

Or, \(49+ 576 = 625\) { There is no need to calculate 24^2 as units digit rule 4^2 = 6 will work wonder here.....}

\(xx9 + xx6 = 625\)

Hence, answer must be (E) 4
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Is there any other approach other than substituting values for x?
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rahulkhannad
Is there any other approach other than substituting values for x?
If you can memorize some pythagorean triplets such as,

(3,4,5); (5,12,13); (7,24,25); (8,15,17); (9,40,41)

You will easily identify the pattern and deduce that \(\sqrt{x} = 2\), therefore \(x = 4\)
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