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# If X is a positive integer, is X odd? (1) X = 16*Y + 5, where Y is a

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If X is a positive integer, is X odd? (1) X = 16*Y + 5, where Y is a  [#permalink]

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02 Apr 2018, 05:06
00:00

Difficulty:

65% (hard)

Question Stats:

36% (01:27) correct 64% (01:08) wrong based on 15 sessions

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If X is a positive integer, is X odd?

(1) X = 16*Y + 5, where Y is a positive number.

(2) X = Z/5, where Z is a positive number.
Manager
Joined: 23 May 2017
Posts: 235
Concentration: Finance, Accounting
WE: Programming (Energy and Utilities)
Re: If X is a positive integer, is X odd? (1) X = 16*Y + 5, where Y is a  [#permalink]

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02 Apr 2018, 05:45
If X is a positive integer, is X odd?

(1) X = 16*Y + 5, where Y is a positive number.
X = even + odd = odd ; y can take only positive integer: any integer multiplied by 16( even number) will always be even
hence {1} is sufficient

(2) X = Z/5, where Z is a positive number.

X = 5/5 = 1 ODD
X = 10/5 = 2 EVEN

hence {2} is not sufficient

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If X is a positive integer, is X odd? (1) X = 16*Y + 5, where Y is a  [#permalink]

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02 Apr 2018, 06:23
amanvermagmat wrote:
If X is a positive integer, is X odd?

(1) X = 16*Y + 5, where Y is a positive number.

(2) X = Z/5, where Z is a positive number.

1. $$Y$$ is a positive number and $$X = 16*Y + 5$$

If Y = 1, X = 5+16 = 21(which is odd)
If Y = $$\frac{1}{16}$$, X = 1+5 = 6(which is even) (Insufficient)

2. $$Z$$ is a positive number and $$X = \frac{Z}{5}$$

If Z = 5, X = 1(which is odd)
If Z = 10, X = 2(which is even) (Insufficient)

On combining the information in both the statements,
as per explanation given for the individual statements,
X can be either EVEN or ODD (Insufficient - Option E)
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Re: If X is a positive integer, is X odd? (1) X = 16*Y + 5, where Y is a  [#permalink]

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02 Apr 2018, 06:29
Clearly missed the Integer part in statement 1.

Agree it is E
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Re: If X is a positive integer, is X odd? (1) X = 16*Y + 5, where Y is a   [#permalink] 02 Apr 2018, 06:29
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