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(1) x + 4 is an odd integer. (2) x/3 is NOT an even integer.

(A) - (1) IS SUFFICIENT, (2) IS NOT

(1) x+4 is odd. Therefore, x+2 is odd, and so is x+0 (i.e. x). Basically, adding a multiple of two to any integer keeps its odd/even'ness' the same.

(2) x/3 is not an even integer. So, it could be - a fraction OR an odd integer. Consider x = 7 . Then x/3 is a fraction. Similarly, x=8 gives x/3 as a fraction. However, x=15 gives an odd quotient. NOT SUFFICIENT.
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(1) x + 4 is an odd integer. (2) x/3 is NOT an even integer.

(1) x + even = odd ---> x - odd ---> sufficient (2) x/3 can be either odd integer or a fraction 2.1. x/3=5 ---> x = 15 ---> yes 2.2. x/3 = 0,5 ---> x = 1,5 ---> no

The answer is A.

(2_new). x/3 is an integer, not even If instead of (2) we had (2_new) then the answer would be D.

gmatclubot

Re: If x is an integer, is x odd? &nbs
[#permalink]
26 Oct 2017, 12:35