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Bunuel
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Bunuel
If x is an integer, is x odd?

(1) x + 4 is an odd integer.
(2) x/3 is NOT an even integer.

x is an integer
Question : is x odd or not.

Statement 1 : x+4 is odd..
Also odd - even = odd
So, odd - 4 = odd = x
SUFFICIENT

Statement 2: x/3 is not even .. So x/3 can be fraction or odd .
If x/3 is odd , definitely x will be odd. For e.g. x/3 = 3 -> x = 9
If x/3 is a fraction, x may be odd or even. For e.g. if x/3 = 2/3 a fraction -> x=2
Also if x/3 = 7/3 a fraction -> x = 7
NOT SUFFICIENT

Answer A
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If x is an integer, is x odd?

(1) x + 4 is an odd integer.
(2) x/3 is NOT an even integer.

1)odd + odd is always even,and even +even is always even but odd + even is always odd. so we know that 4 is even that means that x must be odd.
2) odd*even=even even*even=even so we dont know for sure.

OPtion A is correct Answer.
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Bunuel
If x is an integer, is x odd?

(1) x + 4 is an odd integer.
(2) x/3 is NOT an even integer.

Target question: Is x odd?

Some important rules:
1. ODD + ODD = EVEN
2. ODD + EVEN = ODD
3. EVEN + EVEN = EVEN

Statement 1: x + 4 is an odd integer.
Since 4 is EVEN, we have: x + EVEN = ODD
From rule #2 above, we can see that x must be odd
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: x/3 is NOT an even integer.
There are several values of x that satisfy statement 2. Here are two:
Case a: x = 3. Here, x/3 = 3/3 = 1, and 1 is NOT an even integer. In this case, x IS odd
Case b: x = 4. Here, x/3 = 4/3 = 1.333333...., and 1.333333.... is NOT an even integer. In this case, x is NOT odd
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
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