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Bunuel
If x is an integer, which of the following must be an odd integer?

A. 2x + 2
B. 4x + 3
C. 12x-6
D. 13x
E. 14x

Multiple of an EVEN number is always even and if an odd number is added with an even number then the result is must be odd.

The answer is B
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A. 2x + 2 : even(2x) + even(2) = even

B. 4x + 3 : even(2x) + even(2x) + odd = odd

C. 12x - 6: even(12x) - even(6) = even

D. 13x: 13 * 1 = odd; 13 * 2 = even

E. 14x: even(14) * x = even

Answer B
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Bunuel
If x is an integer, which of the following must be an odd integer?

A. 2x + 2
B. 4x + 3
C. 12x-6
D. 13x
E. 14x
Solution:

Since 4x is even regardless of what integer x is and 3 is odd, 4x + 3 = even + odd = odd.

Answer: B
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The question asks which expression MUST be odd for every integer x. The key principle here is:

Even + Odd = Always Odd
Even + Even = Always Even
Odd × Anything = Could be either

Let's test each choice:

A) 2x + 2 = 2(x + 1) — This has a factor of 2, so it's ALWAYS EVEN. Eliminate.

B) 4x + 3 — Since 4 times any integer is always even, 4x is even. Adding 3 (an odd number) to an even number ALWAYS gives an odd number. This MUST be odd. This is our answer!

But let's confirm by eliminating the rest:

C) 12x - 6 = 6(2x - 1) — This has a factor of 6, so it's ALWAYS EVEN. Eliminate.

D) 13x — If x = 1, this is 13 (odd). If x = 2, this is 26 (even). So it's NOT always odd. Eliminate.

E) 14x = 2(7x) — This has a factor of 2, so it's ALWAYS EVEN. Eliminate.

Answer: B

Key Insight: The general principle to remember: Even number + Odd number = ALWAYS Odd. In 4x + 3, the 4x part is always even (any number multiplied by an even number is even), and 3 is always odd. So the result must always be odd.
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