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22 Aug 2017, 03:19
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:42) correct
27%
(01:44)
wrong
based on 280
sessions
History
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Not Attempted Yet
If integer x is greater than 0 but less than 10 and \(k = x^9\), what is the value of integer k?
(1) x^2 has a units digit of 1.
(2) \(x^{(–2)} < \frac{1}{50}\)
(1) x^2 has a units digit of 1.
(2) \(x^{(–2)} < \frac{1}{50}\)
Updated on: 22 Aug 2017, 04:05
Originally posted by sandeep211986 on 22 Aug 2017, 04:01.
Last edited by sandeep211986 on 22 Aug 2017, 04:05, edited 1 time in total.
Last edited by sandeep211986 on 22 Aug 2017, 04:05, edited 1 time in total.
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Bunuel
Answer has to be C because from statement 1 we get x = 1, 9 while from statement 2 x can be 8 or 9 .
Hence statement C is sufficient to ans the question because combining we get x to be 9.
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22 Aug 2017, 04:02
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Bunuel
Statement 1
- Since \(0<x<10\), we have 9 integer options for X.
- From that 9 options, we have two integers with 1 unit digit : \(1^2\) and \(9^2\).
- Therefore, INSUFFICIENT.
Statement 2
- \(\frac{1}{x^2} < \frac{1}{50}\).
- Since X is a positive number, we can cross multiply without change the sign.
- \(50 < x^2\), or \(X^2 > 50\). We have different possibilities here. X can be 8 and 9.
- Therefore, INSUFFICIENT.
Statement 1&2
- We can conclude that X must be 9.
- SUFFICIENT.
C
