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Re: If x is negative, is x <-3? (1) x^2 > 9 (2) x^3 < [#permalink]

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19 May 2011, 13:16

from stmnt (2) x.x.x<-9 if x=-3 , x.x.x=-27 ,-27<-9 , -3>-3 the answer is no if x=-4 ,x.x.x=-64, -64<-9 , -4>-3 the answer is no by taking different values we can conclude that x is not greater than -3.

by taking x=-2, x.x.x=-8, -8 is not less than -9 ,which makes statement (2) false.

Re: If x is negative, is x <-3? (1) x^2 > 9 (2) x^3 < [#permalink]

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19 May 2011, 13:40

TomB wrote:

from stmnt (2) x.x.x<-9 if x=-3 , x.x.x=-27 ,-27<-9 , -3>-3 the answer is no if x=-4 ,x.x.x=-64, -64<-9 , -4>-3 the answer is no by taking different values we can conclude that x is not greater than -3.

by taking x=-2, x.x.x=-8, -8 is not less than -9 ,which makes statement (2) false.

Then answer is (d)

Is my above reasoning correct. plz explain

What if x=-2.5. Nowhere it's mentioned that x must be an integer.
_________________

(1) x^2 > 9 --> \(x<-3\) or \(x>3\) as given that \(x<0\) then we have that \(x<-3\). Sufficient.

(2) x^3 < –9 --> if \(x=-3\) (\(x^3=-27<-9\)) then the answer will be NO (as \(x\) equals to -3 and is not less than -3) but if \(x=-4\) (\(x^3=-64<-9\)) then the answer will be YES. Not sufficient.