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Math Expert V
Joined: 02 Sep 2009
Posts: 58443
If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y)>0?  [#permalink]

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Difficulty:   85% (hard)

Question Stats: 50% (02:02) correct 50% (01:47) wrong based on 158 sessions

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If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y) > 0?

(1) x > y
(2) |x| > |y|

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Manager  B
Joined: 01 Jul 2010
Posts: 58
Location: India
GMAT 1: 660 Q43 V38 GPA: 3.4
Re: If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y)>0?  [#permalink]

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4
1
The question basically asks are both x+y and x-y positive or negative?

(1) x > y
(2) |x| > |y|

Stmnt 1:
x-y> 0 => x-y is positive
says nothing about x+y which can either be positive or negative
Insufficient

Stmnt 2
$$\sqrt{x^2}>\sqrt{y^2}$$
x^2-y^2 > 0
(x+y)(x-y) > 0
so both x+y and x-y can be positive or
both x+y and x-y can be negative
This means that x+y /x-y will always be positive and greater than 0
Sufficient

Ans B
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Joined: 06 May 2018
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WE: Information Technology (Consulting)
Re: If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y)>0?  [#permalink]

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1
(x + y)/(x - y) = (x + y)(x - y) / (x - y) (x - y) = (x^2 -y^2)/(x - y)^2
we know x is not equal to y , so (x - y)^2 is always > 0
Therefore x^2 - y^2 > 0
So , x^2 > y^2
Hence, |x| > |y|.

Ans- B
Intern  B
Joined: 01 Oct 2017
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GMAT 1: 650 Q43 V33 GRE 1: Q150 V150 GPA: 4
If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y)>0?  [#permalink]

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$$\frac{x+y}{x-y} > 0$$

Multiplying numerator and denominator by x-y, we get,

$$x^2-y^2 >0$$ i.e. $$x^2>y^2$$ and hence |x| > |y|

1. x>y is clearly not sufficient
2|x|>|y| , this what our deduced expressions ask for!

Hence, B
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Joined: 06 Nov 2016
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Location: Viet Nam
Concentration: Strategy, International Business
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Re: If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y)>0?  [#permalink]

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Bunuel wrote:
If x ≠ y and x and y are non-zero integers, is (x+y)/(x−y) > 0?

(1) x > y
(2) |x| > |y|

(1) x > y

If x=2, y=1 then (x+y)/(x−y) = 3/1 = 3 > 0 --> Yes.
If x=1, y=-1 then (x+y)/(x−y) = 0/2 = 0 --> No.
--> Not sufficient.

(2) |x| > |y| --> $$x^2 > y^2$$ --> $$x^2-y^2 > 0$$ --> $$(x+y)(x-y) > 0$$ --> $$(x+y)$$/$$(x−y)$$ $$> 0$$ --> Yes --> Sufficient.

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