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If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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22 Feb 2008, 13:01
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If x > y, x < 6, and y > 3, what is the largest prime number that could be equal to x + y? A. 11 B. 13 C. 7 D. 5 E. 2
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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22 Feb 2008, 14:56
Im going with 7
X>Y X<6 Y>3
Possible X Possible Y 5 2 = 7 5 0
Primes: 3, 5, 7, 11, 13, etc.



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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22 Feb 2008, 15:18
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jimmyjamesdonkey wrote: If x>y, x<6, and y> 3, what is the largest prime number that could be equal to x+y? Primes: 2, 3, 5, 7, 11, 13, 17, etc If X is less than 6 and y is less than X, then 6+6 = 12 would be impossible. We know 13 and all the primes > 13 are out. Let's try 11. 5.9 + 5.1 = 11 5.9 < 6 5.1 < 5.9 everything checks out Answer 11Only trick is to remember there aren't any restrictions on the numbers, ie they don't have to be integers.



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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24 Jun 2008, 10:47
Question: If x>y, x<6 and y > 3, what is the largest prime number that could be equal to x+y ? My answer: sorting out inequalities here, simplified form is 3 < y < x < 6 So as per this x not equals y and is less greater than x. As x is <6, largest possible value is 5. Hence largest possible value for y is 4 (as it should be < x). Maximum SUM (x+y) =10 and largest prime possible is 7 As per MGMAT explanation answer is 11. Here is the explanation from the book which doesn't make sense to me: "The upper extreme for x is less than 6. The upper extreme for y is also < 6 as long as it is less than x. Therefor, x+y must be less than 12.The larget prime number less than 12 is 11". The part I am not clear here is "The upper extreme for y is also < 6 as long as it is less than x". How it can be ever > 4 as it should be always less than x which in turn should be < 6 ?



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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24 Jun 2008, 10:54
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The question does not state that x and y are integers. So x must be less than 6 Make x = 5.999999 Make y = 5.111111 Now x + y = 11. pbvmba wrote: Question: If x>y, x<6 and y > 3, what is the largest prime number that could be equal to x+y ? My answer: sorting out inequalities here, simplified form is 3 < y < x < 6 So as per this x not equals y and is less greater than x. As x is <6, largest possible value is 5. Hence largest possible value for y is 4 (as it should be < x). Maximum SUM (x+y) =10 and largest prime possible is 7 As per MGMAT explanation answer is 11. Here is the explanation from the book which doesn't make sense to me: "The upper extreme for x is less than 6. The upper extreme for y is also < 6 as long as it is less than x. Therefor, x+y must be less than 12.The larget prime number less than 12 is 11". The part I am not clear here is "The upper extreme for y is also < 6 as long as it is less than x". How it can be ever > 4 as it should be always less than x which in turn should be < 6 ?
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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24 Jun 2008, 11:03
Rewrite 3 < y < x < 6. We know that if x > y, then you can assign the highest possible value for x, and the next highest value possible value for y. It didn't say y or x had to be a negative number, so I allowed y and x to be positive.
I plugged in 5.99 for x and 5.98 for y = 11.97. Since that's not a prime, the next possible number down is 11.



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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21 Nov 2010, 09:45
Guys, i have a question here from the MGMAT but I can't understand the answer to the following question : If x>y, x<6, and y>3, what is the largest prime number that could be equal to x + y ? could someone help ?



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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21 Nov 2010, 09:53



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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21 Nov 2010, 10:01
In fact the answer is 11. I think that the trap in this question was assuming that x and y are integers.
Thank you bunnel !



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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31 Mar 2011, 10:40
kamalkicks wrote: Q1. if x>y, x<6, and y>3 what is the largest prime number that could be equal to x+y
kindly solve... and check what is the answer  11 or 7 x=5.6 y=5.4 x>y 5.6>5.4 x<6 5.6<6 y>3 5.4>3 x+y=5.6+5.4=11
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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31 Mar 2011, 19:15
>>>> if x>y, x<6, and y>3 These conditions just tell you that on the number line, both x and y lie between 3 and 6 and that x is to the right of y: Attachment:
Ques2.jpg [ 2.86 KiB  Viewed 3968 times ]
>>>>>what is the largest prime number that could be equal to x+y The maximum value x and y can take is a little less than 6 so their sum must be a little less than 12. The largest prime less than 12 is 11. You can make 11 in a number of ways: (5.6 = x, 5.4 = y), (5.8 = x, 5.2 = y) etc. They don't say that x and y must be integers. Had they said that, then the greatest sum would have been 7 (4 = x, 3 = y)
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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31 Mar 2011, 21:34
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If y > 3, then x > 3 So we have 3 < x < 6 and 3 < y < 6 => x + y < 12 To get the maximum value of x+y we have to maximize both x and y in way that y < x so x can be max like 5.9 and y = 5.1, and this results in (x+y) becoming a prime number as 11 (11 is the biggest prime number < 12)
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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02 Apr 2011, 14:03
x,y need not be integers.
Given x<6 y>3 x>y => 3<x<6 3<y<x
sum cannot be greater than 12 maximum value of x+y = maximum of x + maximum of y =5.9 +5.1
Answer 11.



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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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07 Apr 2011, 04:06
1) If x>y, x<6 and y>3, what is the largest prime number that could be equal to x+y? as x<6 max x can be 5 y>3 to get the largest prime number equal to x+y y= 2 x+y = 52 = 3 Which is not correct. i want to know why? Second method if we line up If we line up the inequalities we get 3<y<x<6 But how to proceed further and how we get OA 11 Pls help
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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04 Sep 2011, 09:00
info given: 3 < y < 6 3 < x < 6 adding all extremes for x+y: 33 = 6 3+6 = +3 +63 = +3 +6+6 = +12 6 < x+y < 12 hence, 11 is the largest prime
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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04 Sep 2011, 10:04
excellent question.... my answer was 7 i did reach till 3<y<x<6, then i "assumed" that to get a prime number(which is an integer) , we need to add two integers :O
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Re: If x > y, x < 6, and y > 3, what is the largest prime number that [#permalink]
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22 Sep 2013, 22:42
atewari wrote: If x>y, x<6 and y>3, what is the largest prime number that could be equal to x+y?
I solve the question to have the result as 7 with the inequality expression being 3<y<x<6. Whereas, the Manhattan guide gives a solution as 11 with the same inequality expression. Am I missing something? Yes, you are missing something. Firstly, both x & y are not necessarily integers. Again, y>3, thus, y can take any value as long as y<x and x<6. Had x=6, then y could be any value between {3,6}[not including both the end points]. Thus, Max value of (x+y) <12. The nearest prime =11. For better clarity, assume x=5.9, y=115.9 = 5.1 or x= 5.8, y = 115.8 = 5.2 and so on. Hope this is clear.
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