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# If { (X + Y) / XY } = 1, then y = A) x/ (X-1) B) X/ (X + 1)

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Intern
Joined: 10 Jan 2008
Posts: 39
If { (X + Y) / XY } = 1, then y = A) x/ (X-1) B) X/ (X + 1) [#permalink]

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10 Sep 2008, 17:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If { (X + Y) / XY } = 1, then y =

A) x/ (X-1)

B) X/ (X + 1)

C) (X-1)/ X

D) (X+1)/ X

E) X

I thought that this was a good problem. I used the make up numbers approach, but I was wondering how to solve this by pure algebra. Thanks
Intern
Joined: 10 Jan 2008
Posts: 39
Re: good plug in the numbers problem, but how to solve? [#permalink]

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11 Sep 2008, 05:24
Wow I spazed last night. Thank You.
Re: good plug in the numbers problem, but how to solve?   [#permalink] 11 Sep 2008, 05:24
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# If { (X + Y) / XY } = 1, then y = A) x/ (X-1) B) X/ (X + 1)

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