It is currently 22 Mar 2018, 16:45

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x+y+z>0, is z>1? 1) z>x+y+1 2)x+y+1<0

Author Message
Director
Joined: 29 Aug 2005
Posts: 836
If x+y+z>0, is z>1? 1) z>x+y+1 2)x+y+1<0 [#permalink]

### Show Tags

08 Dec 2008, 14:27
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

If x+y+z>0, is z>1?
1) z>x+y+1
2)x+y+1<0

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Intern
Joined: 05 Oct 2008
Posts: 14
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

08 Dec 2008, 15:49
From 2) we get -z+1 < 0 I.e. z>1 ==> 2) sufficient

1) is not sufficient:
for example, consider (x,y,z)=(-0.5,-0.2,1): x+y+z>0 and z>x+y+1
and for (x,y,z)=(-0.5,-0.2,3): also both inequalities are verified

Manager
Joined: 14 Oct 2008
Posts: 160
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

08 Dec 2008, 16:05
I would go for E.

I didn't understand how statement 2 is sufficient as stated by echizen

according to statement 2 , x+y+1 < 0 , so x+y < -1 , so say x+y = -2

from qs, x+y+z>0 , -2+z>0 , z>2 , but that does not necessarily mean z>1 ??
Hence statement 2 is also insufficient.

Whats the QA ? ( pls post it along with explanation if given )
Senior Manager
Joined: 21 Apr 2008
Posts: 265
Location: Motortown
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

08 Dec 2008, 16:16
botirvoy wrote:
If x+y+z>0, is z>1?
1) z>x+y+1
2)x+y+1<0

B

x+y+z>0
x+y+1+z>1

stmt1 : from z>x+y+1 and x+y+z+1>1 -> z could be 2/3 or >1 - Not Suff
stmt2: since x+y+1<0, z >1 - Suff
Manager
Joined: 30 Sep 2008
Posts: 111
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

08 Dec 2008, 16:17
gameCode wrote:
I would go for E.

I didn't understand how statement 2 is sufficient as stated by echizen

according to statement 2 , x+y+1 < 0 , so x+y < -1 , so say x+y = -2

from qs, x+y+z>0 , -2+z>0 , z>2 , but that does not necessarily mean z>1 ??
Hence statement 2 is also insufficient.

Whats the QA ? ( pls post it along with explanation if given )

Q: x+y+z>0 => x + y > - z
(2): x+y+1<0 => x + y < -1

=> -z < -1 => z > 1 => suff
Manager
Joined: 23 Nov 2008
Posts: 79
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

09 Dec 2008, 17:41
gameCode wrote:
I would go for E.

I didn't understand how statement 2 is sufficient as stated by echizen

according to statement 2 , x+y+1 < 0 , so x+y < -1 , so say x+y = -2

from qs, x+y+z>0 , -2+z>0 , z>2 , but that does not necessarily mean z>1 ??
Hence statement 2 is also insufficient.

Whats the QA ? ( pls post it along with explanation if given )

The two inequalities say x+y<-1, and x+y+z>0, therefore, z will need to be greater than 1 (and in your example, greater than 2), otherwise x+y(which is <-1)+z will be less than 0.
SVP
Joined: 07 Nov 2007
Posts: 1760
Location: New York
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

09 Dec 2008, 21:48
botirvoy wrote:
If x+y+z>0, is z>1?
1) z>x+y+1
2)x+y+1<0

1) z>x+y+1
--> z+z >(x+y+z) +1
--> 2z>1 --> z>1/2
Not sufficient

2) )x+y+1<0
--> x+y+z+1<z
--> z>1
Sufficient

B
_________________

Smiling wins more friends than frowning

VP
Joined: 18 May 2008
Posts: 1203
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

09 Dec 2008, 22:01
gameCode wrote:
I would go for E.

I didn't understand how statement 2 is sufficient as stated by echizen

according to statement 2 , x+y+1 < 0 , so x+y < -1 , so say x+y = -2

from qs, x+y+z>0 , -2+z>0 , z>2 , but that does not necessarily mean z>1 ??
Hence statement 2 is also insufficient.

Whats the QA ? ( pls post it along with explanation if given )

If Z>2 then it is definitely greater than 1.
Manager
Joined: 14 Oct 2008
Posts: 160
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

09 Dec 2008, 22:26
yeah i realize my mistake in that one. I get confused in this kind of DS. Thanks everyone.
Director
Joined: 29 Aug 2005
Posts: 836
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

22 Dec 2008, 06:15
OA is indeed B. Thanks everyone!
VP
Joined: 05 Jul 2008
Posts: 1369
Re: DS: OG suppl. 85 [#permalink]

### Show Tags

28 Dec 2008, 13:46
x2suresh wrote:
botirvoy wrote:
If x+y+z>0, is z>1?
1) z>x+y+1
2)x+y+1x+y+1
--> z+z >(x+y+z) +1
--> 2z>1 --> z>1/2
Not sufficient

2) )x+y+1 x+y+z+1 z>1
Sufficient

B

Nice way of doing it by adding Z on both sides.

Got a B

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: DS: OG suppl. 85   [#permalink] 28 Dec 2008, 13:46
Display posts from previous: Sort by