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30 Nov 2021, 23:02
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VeritasKarishma
Hey Karishma, this is how I solved the question. Let me know if my approach was right.
The question says least. Therefore the distance between the 3 should be minimum. I took the smallest odd numbers i.e 3 and 5 as y and z respectively.
Now the question just states integers. Thus the closest even number satisfying the condition is -4 (3-(-4)=7). Thus I simply subtracted -4 from 5= 5-(-4)= 9.
I just wanted to know if I should continue with this logic in similar questions are is the same a wrong approach.
Thanks in advance!
01 Dec 2021, 23:13
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NamaySharma
Yes, the approach is perfectly fine though if I am taking numbers, I would much rather take non negative numbers. Calculations with negative numbers are just more prone to errors. So if I know x is less than y, I would take y to be a greater odd number. Or I would much rather start with x = 0 ( an even integer).
Also, if you would like to direct a question to me, please tag me as VeritasKarishma. I would normally miss an untagged reply to my post.
24 Jun 2024, 12:57
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If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?
A. 6
B. 7
C. 8
D. 9
E. 10
WE can take x= -2 (since it is not mentioned that it is a positive integer)
then y can be taken as 5 so that 5- (-2)>5
z can be taken as 7 so 7-(-2)= 9
A. 6
B. 7
C. 8
D. 9
E. 10
WE can take x= -2 (since it is not mentioned that it is a positive integer)
then y can be taken as 5 so that 5- (-2)>5
z can be taken as 7 so 7-(-2)= 9
