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If x + y = z where x, y and z are positive integers, what is the ratio

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If x + y = z where x, y and z are positive integers, what is the ratio  [#permalink]

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New post 01 Jan 2018, 01:33
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  45% (medium)

Question Stats:

67% (02:19) correct 33% (01:25) wrong based on 27 sessions

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If x + y = z where x, y and z are positive integers, what is the ratio  [#permalink]

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New post 01 Jan 2018, 04:57
Bunuel wrote:
If x + y = z where x, y and z are positive integers, what is the ratio of x to y?

(1) xz = 40
(2) y = 3


Statement 1: \(xz=40=> x(x+y)=40\) (substitute the value of \(z\))

\(=>x^2+yx=40\). two variable one equation, values cannot be calculated. Insufficient

Statement 2: nothing mentioned about \(x\). insufficient

Combining 1 & 2: we get \(x^2+3x-40=0\) (substituting the value of \(y\) from Statement 2)

therefore \(x=-8\) or \(5\). As \(x\) is positive so \(x=5\) & \(y=3\)

Hence \(x:y=5:3\). Sufficient

Option C
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If x + y = z where x, y and z are positive integers, what is the ratio &nbs [#permalink] 01 Jan 2018, 04:57
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