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# If Xn =n^2+8n+20 for n=7, 4, 8, 5, 10, 11, 6, 12, and 9,

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Current Student
Joined: 11 May 2008
Posts: 551
If Xn =n^2+8n+20 for n=7, 4, 8, 5, 10, 11, 6, 12, and 9,  [#permalink]

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29 Jul 2008, 10:25
If Xn =n^2+8n+20 for n=7, 4, 8, 5, 10, 11, 6, 12, and 9, what is the median of all Xn?
A. 68
B. 104
C. 125
D. 144
E. 148

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Senior Manager
Joined: 14 Mar 2007
Posts: 272
Location: Hungary

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29 Jul 2008, 10:35
D. I can explain if it is correct.
Current Student
Joined: 11 May 2008
Posts: 551

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29 Jul 2008, 10:38
hmmm, im getting E... so donno.
Senior Manager
Joined: 14 Mar 2007
Posts: 272
Location: Hungary

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29 Jul 2008, 10:48
Sorry I wanted to say it is E.
VP
Joined: 28 Dec 2005
Posts: 1477

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29 Jul 2008, 20:25
148 for me. The median of all Xn is basically the value when n=8 , as 8 is the median value in the list. Plug it in and you get 148

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# If Xn =n^2+8n+20 for n=7, 4, 8, 5, 10, 11, 6, 12, and 9,

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