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# If xy+z= x(y+z), which of the ff must be true? a. x=0, z=0

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Manager
Joined: 31 Jul 2006
Posts: 233

Kudos [?]: 93 [0], given: 0

If xy+z= x(y+z), which of the ff must be true? a. x=0, z=0 [#permalink]

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12 Oct 2008, 22:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If xy+z= x(y+z), which of the ff must be true?
a. x=0, z=0
b. x=1, y=1
c. y=1, z=0
d. x=1, y=0
e. x=1, z=0

Kudos [?]: 93 [0], given: 0

SVP
Joined: 17 Jun 2008
Posts: 1534

Kudos [?]: 279 [0], given: 0

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13 Oct 2008, 05:10
What is the source of question? It does not seem to be worded properly.

The equation can be simplified to z(x-1) = 0....hence either z = 0 or x = 1.

Kudos [?]: 279 [0], given: 0

Senior Manager
Joined: 21 Apr 2008
Posts: 269

Kudos [?]: 165 [0], given: 0

Location: Motortown

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13 Oct 2008, 05:13
E

xy+z = xy+xz
z= xz
z(x-1) = 0

z=0 x =1

Kudos [?]: 165 [0], given: 0

SVP
Joined: 05 Jul 2006
Posts: 1751

Kudos [?]: 432 [0], given: 49

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13 Oct 2008, 06:51
If xy+z= x(y+z), which of the ff must be true?
a. x=0, z=0
b. x=1, y=1
c. y=1, z=0
d. x=1, y=0
e. x=1, z=0

given

xy+z = xy+xz ie: xz = z (z = 0 or x = 1 or both x,z = 0)

Kudos [?]: 432 [0], given: 49

Manager
Joined: 31 Jul 2006
Posts: 233

Kudos [?]: 93 [0], given: 0

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13 Oct 2008, 18:55
I'm confused too. OA is E. BUt A is possible too right?

Kudos [?]: 93 [0], given: 0

Re: xyz   [#permalink] 13 Oct 2008, 18:55
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