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If y 0 and y -1, which is greater x/y or x/(y+1) ? (1) x 0

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If y 0 and y -1, which is greater x/y or x/(y+1) ? (1) x 0 [#permalink]

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New post 31 Jul 2008, 17:35
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If y≠0 and y≠-1, which is greater x/y or x/(y+1) ?

(1) x≠0
(2) x > y

Is there any better way of solving this w/o using numbers?

Kudos [?]: 135 [0], given: 7

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Kudos [?]: 843 [0], given: 19

Re: another DS with number assumption ! [#permalink]

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New post 31 Jul 2008, 19:35
rao_1857 wrote:
If y≠0 and y≠-1, which is greater x/y or x/(y+1) ?

(1) x≠0
(2) x > y

Is there any better way of solving this w/o using numbers?


I donot think so.

togather: though x is not equal to 0 and > y, x and y can be any value i.e. +ve or -ve or both.

if x = 1 and y = -2, x/y < x/(y+1)
if x = 2 and y = 1, x/y > x/(y+1)
E.
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Kudos [?]: 843 [0], given: 19

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Re: another DS with number assumption ! [#permalink]

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New post 31 Jul 2008, 20:21
same, E for me. i think the quickest way is to check numbers, specifically negative #s for this question ....

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Re: another DS with number assumption ! [#permalink]

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New post 03 Aug 2008, 03:52
rao_1857 wrote:
If y≠0 and y≠-1, which is greater x/y or x/(y+1) ?

(1) x≠0
(2) x > y

Is there any better way of solving this w/o using numbers?


always |x/y| >|x/(y+1)|
now we need to know what are the signs of x and y ,consider (1) it does not talk abt sign of x or y if say x/y is -ve then x/(y+1) is also -ve and hence x/y < x/(y+1)

say x/y is +ve then opp is result hence (1) is insufficient

consider (2) x>y does not again suggest sign of x/y hence this insufficien

(1) and (2) dont together suggest sign of x/y hence insufficient

IMO E
this is the alternative way i used .Hope this helps.
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Re: If y 0 and y -1, which is greater x/y or x/(y+1) ? (1) x 0 [#permalink]

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New post 03 Oct 2017, 19:11
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Kudos [?]: 273 [0], given: 0

Re: If y 0 and y -1, which is greater x/y or x/(y+1) ? (1) x 0   [#permalink] 03 Oct 2017, 19:11
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