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If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1

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If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1 [#permalink]

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New post 13 Apr 2018, 02:10
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

71% (01:00) correct 29% (01:38) wrong based on 17 sessions

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Joined: 28 Apr 2014
Posts: 49
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If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1 [#permalink]

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New post Updated on: 13 Apr 2018, 03:19
IMO B

St1 y>1 or y<-1
insufficient

St2 y^2+y>y^2 (sq quantity is +ve)
y>0
sufficient

Originally posted by NiharikaR on 13 Apr 2018, 02:13.
Last edited by NiharikaR on 13 Apr 2018, 03:19, edited 1 time in total.
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Re: If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1 [#permalink]

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New post 13 Apr 2018, 03:15
Bunuel wrote:
If y ≠ 0, is y > 0?


(1) \(|y| > 1\)

(2) \(\frac{y^2 + y}{y^2} > 1\)



NiharikaR, ans should be B..

(1) \(|y| > 1\)
tells us that y<-1 or y>1
insuff

(2) \(\frac{y^2 + y}{y^2} > 1\)..
Cross multiply as y^2 is POSITIVE
\(y^2 + y > y^2.............y>y^2-y^2.......y>0\)..
suff

B
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If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1 [#permalink]

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New post 13 Apr 2018, 03:27
Thanks. I read the question wrong. I thought its asking y>1.
Though I got y>0, I wrote insufficient.

I have to avoid such silly mistakes during exam
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Re: If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1 [#permalink]

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New post 13 Apr 2018, 06:12
I ) |y| > 1

y>1
y <-1

not sufficient

II)
\(y^2+y/y^2\) > 1

y^2/y^2 + y/y^2 > 1

1 + 1/y >1 ==> 1/y >0 ==> y>0

sufficient

Therefore B
Re: If y ≠ 0, is y > 0? (1) |y| > 1 (2) y^2 + y/y^2 > 1   [#permalink] 13 Apr 2018, 06:12
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