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If y>=0, what is the value of X? A. !X-3!>=Y B.

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If y>=0, what is the value of X? A. !X-3!>=Y B. [#permalink]

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New post 07 Jan 2009, 01:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If y>=0, what is the value of X?
A. !X-3!>=Y
B. !X-3!<=-Y


looking for your cordial participation?

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New post 07 Jan 2009, 02:51
If y>=0, what is the value of X?
A. !X-3!>=Y
B. !X-3!<=-Y

From Stmt 1--->
Lets take Y as 2 (as y >= 0)
we get, |x-3|>=2
Here X can have any values like 5,6,7....etc
Hence not sufficient

From Stmt 2---->
As per the question stem, the possible values of Y can be 0,1,2,3....etc
Now a modular value cannot be anything but 0.
Hence, |x-3|=0 and x = -3
Sufficient

Answer is B

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New post 07 Jan 2009, 03:06
sandipchowdhury wrote:
If y>=0, what is the value of X?
A. !X-3!>=Y
B. !X-3!<=-Y

From Stmt 1--->
Lets take Y as 2 (as y >= 0)
we get, |x-3|>=2
Here X can have any values like 5,6,7....etc
Hence not sufficient

From Stmt 2---->
As per the question stem, the possible values of Y can be 0,1,2,3....etc
Now a modular value cannot be anything but 0.
Hence, |x-3|=0 and x = -3
Sufficient

Answer is B


Sandip i think u have missed something i.e y>=0 so we can also take y=0 ..
no put the value in 1 and calculate

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New post 07 Jan 2009, 12:18
the answer is b

if you have y>=0 and |x-3|>=-y, then the only possible value for y is y=0. and then you get the value of x.

try posting it at gmatgremath.blogspot.com if you want a gmat tutor's official answer.

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New post 09 Jan 2009, 01:47
can any one elaborate - st:B

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New post 09 Jan 2009, 02:07
can someone please explain the question more clearly

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Re: source GMATPrep [#permalink]

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New post 10 Jan 2009, 00:26
let me try:

sandipchowdhury wrote:
If y>=0, what is the value of X?
A. !X-3!>=Y
B. !X-3!<=-Y

From Stmt 1--->
Lets take Y as 2 (as y >= 0)
we get, |x-3|>=2
Here X can have any values like 5,6,7....etc
Hence not sufficient

From Stmt 2---->
As per the question stem, the possible values of Y can be 0,1,2,3....etc
Now a modular value cannot be anything but 0.
Hence, |x-3|=0 and x = -3
Sufficient

Answer is B


Sandeep's first part is clear that x can h ave multiple values. Gurmeet , you are correct that y can be 0 in which case x=3. But still, y can be 1 also, in which case x can have multiple values. Hence A is not sufficient.

Now coming to (2),

Since, y >=0, it means that -y <=0 which implies |x-3|<=0 (since |x-3|<=y). Now the left hand (|x-3|)is a modulus which can never be negative, it can only be greater than or equal to 0.

Which implies |x-3| = 0 --> x=3. Hence (B) is sufficient.

I hope this was bit clear.
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Re: source GMATPrep [#permalink]

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New post 10 Jan 2009, 01:27
let me try:


sandipchowdhury wrote:
If y>=0, what is the value of X?
A. !X-3!>=Y
B. !X-3!<=-Y

From Stmt 1--->
Lets take Y as 2 (as y >= 0)
we get, |x-3|>=2
Here X can have any values like 5,6,7....etc
Hence not sufficient

From Stmt 2---->
As per the question stem, the possible values of Y can be 0,1,2,3....etc
Now a modular value cannot be anything but 0.
Hence, |x-3|=0 and x = -3
Sufficient

Answer is B


Sandeep's first part is clear that x can h ave multiple values. Gurmeet , you are correct that y can be 0 in which case x=3. But still, y can be 1 also, in which case x can have multiple values. Hence A is not sufficient.

Now coming to (2),

Since, y >=0, it means that -y <=0 which implies |x-3|<=0 (since |x-3|<=y). Now the left hand (|x-3|)is a modulus which can never be negative, it can only be greater than or equal to 0.

Which implies |x-3| = 0 --> x=3. Hence (B) is sufficient.

I hope this was bit clear.
let me try:

sandipchowdhury wrote:
If y>=0, what is the value of X?
A. !X-3!>=Y
B. !X-3!<=-Y

From Stmt 1--->
Lets take Y as 2 (as y >= 0)
we get, |x-3|>=2
Here X can have any values like 5,6,7....etc
Hence not sufficient

From Stmt 2---->
As per the question stem, the possible values of Y can be 0,1,2,3....etc
Now a modular value cannot be anything but 0.
Hence, |x-3|=0 and x = -3
Sufficient

Answer is B


Sandeep's first part is clear that x can h ave multiple values. Gurmeet , you are correct that y can be 0 in which case x=3. But still, y can be 1 also, in which case x can have multiple values. Hence A is not sufficient.

Now coming to (2),

Since, y >=0, it means that -y <=0 which implies |x-3|<=0 (since |x-3|<=y). Now the left hand (|x-3|)is a modulus which can never be negative, it can only be greater than or equal to 0.

Which implies |x-3| = 0 --> x=3. Hence (B) is sufficient.

I hope this was bit clear.


i think you want to write since |x-3|<=-y

if it is then a very good explaination.

thanks
Shobuj

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Re: source GMATPrep [#permalink]

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New post 10 Jan 2009, 01:36
yes, that is what I meant
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Re: source GMATPrep [#permalink]

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New post 10 Jan 2009, 08:56
krishan and other members thanks a lot for a nice expanation

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Re: source GMATPrep   [#permalink] 10 Jan 2009, 08:56
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