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# If y >=0, what is value of x 1) /x-3/ >=y 2) /x-3/

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Manager
Joined: 22 Jul 2006
Posts: 50
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Kudos [?]: 3 [0], given: 0

If y >=0, what is value of x 1) /x-3/ >=y 2) /x-3/ [#permalink]

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28 Oct 2006, 15:50
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If y >=0, what is value of x

1) /x-3/ >=y
2) /x-3/ <=-y
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 48 [0], given: 0

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28 Oct 2006, 18:13
Sam Kana wrote:
If y >=0, what is value of x

1) /x-3/ >=y
2) /x-3/ <=-y

D?

|x-3| => x-3=y and 3-x=y

since y>=0 then x has to be 3 to satisfy both equations.
Manager
Joined: 22 Jul 2006
Posts: 50
Followers: 0

Kudos [?]: 3 [0], given: 0

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28 Oct 2006, 19:51
I am waiting to see alternative solution procedures, I will post the answer soon..
VP
Joined: 25 Jun 2006
Posts: 1167
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29 Oct 2006, 19:32
B.

from 1st, you dont get any specific value of x.

from 2. |x-3| must = 0. so x = 3.

hence B>
29 Oct 2006, 19:32
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