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If y = 12x – 17, then the least integer x for which y is greater than
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22 May 2020, 06:22
22 May 2020, 06:22
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If y = 12x – 17, then the least integer x for which y is greater than 100 is
A. 7
B. 8
C. 9
D. 10
E. 11
PS21247
A. 7
B. 8
C. 9
D. 10
E. 11
PS21247
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Joined: 12 Sep 2015
Posts: 6804
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Location: Canada
If y = 12x – 17, then the least integer x for which y is greater than
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Updated on: 22 May 2020, 09:21
Updated on: 22 May 2020, 09:21
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Bunuel wrote:
If y = 12x – 17, then the least integer x for which y is greater than 100 is
A. 7
B. 8
C. 9
D. 10
E. 11
PS21247
A. 7
B. 8
C. 9
D. 10
E. 11
PS21247
Given: y = 12x – 17
The least integer x for which y is greater than 100 is
So, we want: y > 100
Replace y with 12x – 17 to get: 12x – 17 > 100
Add 17 to both sides of the inequality to get: 12x > 117
Divide both sides by 12 to get: x > 117/12
No need to grab your calculator!
Since 108/12 = 9 and since 120/12 = 10, we know that 117/12 = 9.something
So we get: x > 9.something
Since x must be an INTEGER, the smallest possible value of x is 10
Answer: D
Cheers,
Brent
Originally posted by BrentGMATPrepNow on 22 May 2020, 08:00.
Last edited by BrentGMATPrepNow on 22 May 2020, 09:21, edited 1 time in total.
Last edited by BrentGMATPrepNow on 22 May 2020, 09:21, edited 1 time in total.
General Discussion
Re: If y = 12x – 17, then the least integer x for which y is greater than
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22 May 2020, 06:24
22 May 2020, 06:24
D.
X =10
Then Y will be 103
Posted from my mobile device
X =10
Then Y will be 103
Posted from my mobile device
