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# If (y^2 + 1)^(1/2) = 2, what is the value of y ?

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Math Expert
Joined: 02 Sep 2009
Posts: 43806
If (y^2 + 1)^(1/2) = 2, what is the value of y ? [#permalink]

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07 Sep 2017, 22:56
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Difficulty:

35% (medium)

Question Stats:

64% (00:40) correct 36% (00:54) wrong based on 56 sessions

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If $$\sqrt{y^2 + 1}= 2$$, what is the value of y ?

(1) y > 0
(2) y > -1.5
[Reveal] Spoiler: OA

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Joined: 12 Feb 2017
Posts: 71
Re: If (y^2 + 1)^(1/2) = 2, what is the value of y ? [#permalink]

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07 Sep 2017, 23:30
1
KUDOS
√(y^2 +1) = 2
square both sides
y^2+1=4
y^2=3
y= +-√3 -----(or y= +- 1.72)

stmt 1) y > 0
if y>0 , y can take only one value i.e. y= √3
Hence statement 1) is sufficient.

stmt 2) y > -1.5
if y> -1.5 , y can take only one value i.e. y= √3 ----(√3= 1.72)
Hence statement 2) is sufficient.

Kudos if it helps.
Re: If (y^2 + 1)^(1/2) = 2, what is the value of y ?   [#permalink] 07 Sep 2017, 23:30
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